4*(n + 1) = 6*n*3
The series is a(n) = 4n² +5n. . . and this is the general formula which also gives the nth term. When n = 1, 4n² + 5n = 4*1 + 5*1 = 9 When n = 2, 4n² + 5n = 4*4 + 5*2 = 26 . . .and so on When n = 5, 4n² + 5n = 4*25 + 5*5 = 125. The series can be determined using the Difference Technique. A second difference of 8 gives the first term 4n². . . . as a 2nd difference of 2 equates to n². After applying this to the original series, the revised series produces a 1st difference of 5, hence 5n.
In an arithmetic progression the difference between each term (except the first) and the one before is a constant. In a geometric progression, their ratio is a constant. That is, Arithmetic progression U(n) - U(n-1) = d, where d, the common difference, is a constant and n = 2, 3, 4, ... Equivalently, U(n) = U(n-1) + d = U(1) + (n-1)*d Geometric progression U(n) / U(n-1) = r, where r, the common ratio is a non-zero constant and n = 2, 3, 4, ... Equivalently, U(n) = U(n-1)*r = U(1)*r^(n-1).
5 - 2n = 1 4 = 2n n = 2
n=number x 1 and n2 is n x n
The way to write out the difference of 9 and a number is n-9.
n - 2 = 4
4n-8
The main difference seen is in the extra 'n', possibly Nitrogen, in the first substance. What that change means to reactivity is outside my knowledge
Suppose the number is N then 4N = 3*abs(35-N) where abs(35-N) is the difference between 35 and N If N > 35 then 4*N = 3*(N-35) = 3*N - 105 So N = -105 If N < 35 then 4*N = 3*(35-N) = 105 - 3*N So 7*N = 105 ie N = 15 So N = -105 or 15
4*(n + 1) = 6*n*3
It is 3*abs(n - 6) + 4*n
This is an Arithmetic Series/Sequence. In general the nth term, A(n) = a + (n - 1)d....where a is the 1st term and d is the common difference. In this question, the 1st term equals 1 and the common difference is 4. Then the nth term, A(n) = 1 + (n - 1) x 4 = 1 + 4n - 4 = 4n - 3.
the double of n is m. is the difference between m and n
Since n is positive, |n| = n, so you have 2n - n = n. The difference is n.
In an arithmetic progression the difference between each term (except the first) and the one before is a constant. In a geometric progression, their ratio is a constant.That is,Arithmetic progressionU(n) - U(n-1) = d, where d, the common difference, is a constant and n = 2, 3, 4, ...Equivalently,U(n) = U(n-1) + d = U(1) + (n-1)*dGeometric progressionU(n) / U(n-1) = r, where r, the common ratio is a non-zero constant and n = 2, 3, 4, ...Equivalently,U(n) = U(n-1)*r = U(1)*r^(n-1).
The series is a(n) = 4n² +5n. . . and this is the general formula which also gives the nth term. When n = 1, 4n² + 5n = 4*1 + 5*1 = 9 When n = 2, 4n² + 5n = 4*4 + 5*2 = 26 . . .and so on When n = 5, 4n² + 5n = 4*25 + 5*5 = 125. The series can be determined using the Difference Technique. A second difference of 8 gives the first term 4n². . . . as a 2nd difference of 2 equates to n². After applying this to the original series, the revised series produces a 1st difference of 5, hence 5n.