Chat with our AI personalities
4*(n + 1) = 6*n*3
The series is a(n) = 4n² +5n. . . and this is the general formula which also gives the nth term. When n = 1, 4n² + 5n = 4*1 + 5*1 = 9 When n = 2, 4n² + 5n = 4*4 + 5*2 = 26 . . .and so on When n = 5, 4n² + 5n = 4*25 + 5*5 = 125. The series can be determined using the Difference Technique. A second difference of 8 gives the first term 4n². . . . as a 2nd difference of 2 equates to n². After applying this to the original series, the revised series produces a 1st difference of 5, hence 5n.
In an arithmetic progression the difference between each term (except the first) and the one before is a constant. In a geometric progression, their ratio is a constant. That is, Arithmetic progression U(n) - U(n-1) = d, where d, the common difference, is a constant and n = 2, 3, 4, ... Equivalently, U(n) = U(n-1) + d = U(1) + (n-1)*d Geometric progression U(n) / U(n-1) = r, where r, the common ratio is a non-zero constant and n = 2, 3, 4, ... Equivalently, U(n) = U(n-1)*r = U(1)*r^(n-1).
5 - 2n = 1 4 = 2n n = 2
n=number x 1 and n2 is n x n