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If a rectangle has 50 inches what is its length and width?
If "50 inches" is the perimeter all you can say is that length plus width = 25 inches.
What is the length and width of a perimeter of 100ft?
Assuming that the length is at least as great as the width, the length can have any value, L, between 25 and 50 feet. The width, W, then would be 50 - L feet.
What is the volume of a cake with 50 cm length and 20 cm width?
We can not tell you because volume requires a third dimension.
If the perimeter is 150 and if the length is twice the width than what is the length and the width?
If length is "l" and width is "w", then the equation can be written as:2l+2w=150because we know that in a quadrilateral, the perimeter is the length plus the length plus the width plus the width, or 2 times the length plus 2 times the width.To simplify 2l+2w=150, we can divide each side by two:2l+2w=150 (150 divided by 2= 75)l+w =75Now we know that the length plus the width is 75 units.We know that the length is twice the length is twice the width, or:l=2wWe can substitute this in for the length.l+w =75(2w)+w =753w=75Now, we can divide each side by 3 to get the width:3w=75 (75 divided by 3= 25)w=25The width=25 unitsNow, we can figure out what the length is by putting in 25 for the width:l+w=75l+(25)=75We can subtract each side by 25:l+25=75 (75-25=50)l=50The length=50 unitsWe know this is correct because 50 (the length) is two times 25 (the width)
The roller skating rink has a perimeter of 150 yards. If the length is twice as long as the width what are the dimensions of the rink?
The dimensions are length 50 yards and width 25 yards
Ben is planning to fence his rectangular garden the area of the garden is 50 square feet and the lenght of the garden is twice the width what is the width of the fence?
Let the length be 2x and the width be x: length*width = area 2x*x = 50 2x2 = 50 x2 = 25 x = 5 feet
What is the width of the rectangle if A rectangle is 25 centimeters long and The perimeter is 84 centimeters.?
To find the width of the rectangle, we need to subtract twice the length from the perimeter. Given that the length is 25 centimeters and the perimeter is 84 centimeters, twice the length would be 50 centimeters. Subtracting 50 from 84 gives us a width of 34 centimeters for the rectangle.
The perimeter of a rectangle is 130m. The length of the rectangle is 25m more than the width. What are the lengths and widths of the rectangle?
x=width x+25=length 4x+50=130 4x=80 x=20 width is 20 length is 45
The area of the garden is 50 square feet and the length of the garden is twice the width What is the length of the fence?
The formula for finding the area of a rectcngle is: L * W = A Let x represent the width and 2x represent the length (twice the width). Set up the equation and solve: 2x * x = 50 (then simplify) 2x² = 50 (then divide both sides to find the value of x²) x² = 25 (then find the square root of 25 to solve for x) x = 5 the width (x) = 5, and the length (2x) = 10
The length of a rectangle is twice its width If the area of the rectangle is less than 50 square meters what is the greatest width of the rectangle?
From the statement of the problem, if w is the width, the area is 2w2 , the product of the width and the length, which is stated to be twice the width. Since 2w2 must be less than 50, w2 < 25, and the width must be less than 5 meters.
If rectangle has perimeter of 50 cm Find length and width?
length 18 width 7
How do you find the width of a rectangle if the length is 12 cm and the perimeter is 50?
The perimeter is found by multiplying the width by the length. So divide 50 by 12 and you get 4.166 width.
