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you have two equations with two unknowns, length and width

let W = width and L = length

2W - 4 = L (1)

The perimeter is 2L + 2W

2L + 2W = 34 (2)

rearrange (1) and (2)

2W - L = 4

2W +2L = 34

multiply (1) both sides by 2

4W - 2L = 8

2W + 2L =34

add equations

6W = 42

W = 7

solve L from (2) by substituting W = 7

L = 10

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Q: What is the dimensions of a rectangle if the length is 4 centimeters less than twice its width and the perimeter is 34 centimeters what is the dimensions of a rectangle?
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