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x2+11x+121 = x+96

x2+11x-x+121-96 = 0

x2+10x+25 = 0

Discriminant = b2-4ac = 102-4*1*25 = 0

The discriminant is equal to 0 so the quadratic equation will have two equal roots.

(x+5)(x+5) = 0

Therefore: x = -5 and also x = -5

the answer is 0

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Q: What is the discriminant in the quadratic equation x squared plus 11x plus 121 equals x plus 96?
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