Sqrt[(5-4)2 + (5-4)2] = sqrt[1 + 1] = sqrt(2)
If you mean points of (5, 4) and (5, -4) then the distance works out as 8
Points: (2, 4) and (5, 0) Distance: 5
If you mean points of (5, 5) and (1, 5) then the distance is 4
Pythagoras can be used to find the distance between any two points (x0, y0) and (x1, y1): Distance = √((x1 - x0)² + (y1 - y0)²) → distance = √((5 - 5)² + (13 - 9)²) = √(0 + 4²) = √(4²) = 4.
If you mean: (-8, 4) and (5, 4) Then the distance between the points works out as 13
-2 & 5
120
1
Points: (-4, 5) and (3, 16) Distance: square root of 170 which is about 13
The distance is 5. The x distance is 3, the y distance is 4, and the diagonal issqrt(32 + 42) = sqrt (9 + 16) = sqrt 25 = 5
The distance is 6.4 units.
If you mean points of (5, 5) and (1, 5) then the distance is 4