Points: (-4, 5) and (3, 16)
Distance: square root of 170 which is about 13
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The distance between the points of (4, 3) and (0, 3) is 4 units
(3-1)2 + (5-8)2 = 13 and the square root of this is the distance between the points
I'm assuming that these are 3-D coordinates A(0,0,0) and B(3,4,5) The distance formula between two points in 3 dimensions is the following: D = SQR {(x1-x2)2 + (y1-y2)2 + (z1-z2)2} D = SQR {(0-3)2 + (0-4)2 + (0-5)2} D = SQR {9+16+25} = SQR {50} D is approx. = 7.07
The distance between (3, 7) and (-3, -1) is sqrt{[(3 - (-3)]2 + [7 - (-1)]2} = sqrt{[3 + 3]2 + [7 + 1]2} =sqrt{[6]2 + [8]2} = sqrt{36 + 64} = sqrt{100} = 10 units.
If you mean endpoints (-1, -3) and (11, -8) then by using the distance formula the length between the points is 13 units