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Points: (-4, 5) and (3, 16)

Distance: square root of 170 which is about 13

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9y ago

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What is the distance between the points (37) and (1516) on a coordinate plane?

To find the distance between the points (3, 7) and (15, 16) on a coordinate plane, you can use the distance formula: ( d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ). Plugging in the values, ( d = \sqrt{(15 - 3)^2 + (16 - 7)^2} = \sqrt{12^2 + 9^2} = \sqrt{144 + 81} = \sqrt{225} = 15 ). Therefore, the distance between the points is 15 units.


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