0
√[(X2-X1)2+(Y2-Y1)2]
minus a negative is plus a positive
√[(5+3)2+(-2-4)2]
plus a negative is minus a positive
√(82-62)
√(64-36)
√28 or 2√7
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∙ 13y ago
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What is the distance between the points -4 3 and 3 -1?
Points: (-4, 3) and (3, -1) Distance: (3--4)2+(-1-3)2 = 65 and the square root if this is the distance which is just over 8
What is the distance between points 1 2 and 4 -1?
Use Pythagoras to find the distance between two points (x0,.y0) and (x1, y1): distance = √(change_in_x² + change_in_y²) → distance = √((x1 - x0)² + (y1 - y0)²) → distance = √((4 - 1)² + (-1 -2)²) → distance = √(3² + (-2)²) → distance = √(9 + 9) → distance = √18 = 3 √2
What is the distance between the origin -3 and -4?
It is the square root of (-3-0)2+(-4-0)2 = 5
What is the distance between points 2 4 and 6 3?
Using Pythagoras: distance = √(difference_in_x^2 + difference_in_y^2) = √((6 - 2)^2 + (3 - 4)^2) = √(16 + 1) = √17 ≈ 4.12
What is the distance between the points named by (2 3) and (2 7) on the coordinate plane?
Points: (2, 3) and (2, 7) Distance works out as: 4 units
How can you find the distance between two numbers on a number line?
Just subtract the lowest number from the greatest number. For example, the distance between 3 and 8, is 8 - 3 = 5 units, the distance between -2 and 3, is 3 - (-2) = 3 + 2 = 5 units, the distance between -4 and -2, is -2 - (-4) = -2 + 4 = 2 units.
Find the distance between (-4 2) and (-7 -6). in units?
The distance between the points of (4, 3) and (0, 3) is 4 units
What is the distance between the points -4 3 and 3 -1?
Points: (-4, 3) and (3, -1) Distance: (3--4)2+(-1-3)2 = 65 and the square root if this is the distance which is just over 8
What is the distance between two points -3 7 and -6 4?
(-3-(-6))2 + (7-4)2 = 18 and the square root of this is the distance between the two points
What is the distance between points 1 2 and 4 -1?
Use Pythagoras to find the distance between two points (x0,.y0) and (x1, y1): distance = √(change_in_x² + change_in_y²) → distance = √((x1 - x0)² + (y1 - y0)²) → distance = √((4 - 1)² + (-1 -2)²) → distance = √(3² + (-2)²) → distance = √(9 + 9) → distance = √18 = 3 √2
What is the distance between (3 5) and (3 -4)?
It is the square root of (-3-0)2+(-4-0)2 = 5
What is the distance between the origin -3 and -4?
It is the square root of (-3-0)2+(-4-0)2 = 5
What is the distance between -2 4 and 1 -2?
What is the distance between (4, -2) and (-1,6)?
What is the distance between 1 and -3 on a number line?
4
What is the distance between points 2 4 and 6 3?
Using Pythagoras: distance = √(difference_in_x^2 + difference_in_y^2) = √((6 - 2)^2 + (3 - 4)^2) = √(16 + 1) = √17 ≈ 4.12
What is the distance between the points named by (2 3) and (2 7) on the coordinate plane?
Points: (2, 3) and (2, 7) Distance works out as: 4 units
What is the distance between -8 and plus 4 on a number line?
-8 -7 -6 -5 -4 -3 -2 -1 0 1 2 3 4 There is a distance of 12.
