It is the square root of (-3-0)2+(-4-0)2 = 5
Points: (3, -4) and (3, 3) Distance: 7 units
60
Points: (-4, 3) and (3, -1) Distance: (3--4)2+(-1-3)2 = 65 and the square root if this is the distance which is just over 8
Using the number line ;- ...-5,-4,-3,-2,-1,0,1,2,3,4,5 .... Starting at '-3' and moving to the right to '1'. we make '4' steps/ So the distance is '4'. !!!!
To find the distance between the points (7, -1) and (7, 3), we can use the distance formula. Since both points have the same x-coordinate, the distance is simply the difference in the y-coordinates: |3 - (-1)| = |3 + 1| = 4. Therefore, the distance between the two points is 4 units.
1
The distance between the points of (4, 3) and (0, 3) is 4 units
Points: (3, -4) and (3, 3) Distance: 7 units
The distance between the points of (4, 3) and (0, 3) is 4 units
The distance between points: (9, 4) and (3, 4) is 6
4
3-4 = -1 -21 the distance between -1 and -21 is -20 -20 -1 = -21
60
Just subtract the lowest number from the greatest number. For example, the distance between 3 and 8, is 8 - 3 = 5 units, the distance between -2 and 3, is 3 - (-2) = 3 + 2 = 5 units, the distance between -4 and -2, is -2 - (-4) = -2 + 4 = 2 units.
Points: (-4, 3) and (3, -1) Distance: (3--4)2+(-1-3)2 = 65 and the square root if this is the distance which is just over 8
-4
Using the number line ;- ...-5,-4,-3,-2,-1,0,1,2,3,4,5 .... Starting at '-3' and moving to the right to '1'. we make '4' steps/ So the distance is '4'. !!!!