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What is the distance between the points -4 3 and 3 -1?
Points: (-4, 3) and (3, -1) Distance: (3--4)2+(-1-3)2 = 65 and the square root if this is the distance which is just over 8
What is the distance between points 1 2 and 4 -1?
Use Pythagoras to find the distance between two points (x0,.y0) and (x1, y1): distance = √(change_in_x² + change_in_y²) → distance = √((x1 - x0)² + (y1 - y0)²) → distance = √((4 - 1)² + (-1 -2)²) → distance = √(3² + (-2)²) → distance = √(9 + 9) → distance = √18 = 3 √2
What is the distance between the origin -3 and -4?
It is the square root of (-3-0)2+(-4-0)2 = 5
What is the distance between points 2 4 and 6 3?
Using Pythagoras: distance = √(difference_in_x^2 + difference_in_y^2) = √((6 - 2)^2 + (3 - 4)^2) = √(16 + 1) = √17 ≈ 4.12
What is the distance between the points named by (2 3) and (2 7) on the coordinate plane?
Points: (2, 3) and (2, 7) Distance works out as: 4 units
