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√[(X2-X1)2+(Y2-Y1)2]

minus a negative is plus a positive

√[(5+3)2+(-2-4)2]

plus a negative is minus a positive

√(82-62)

√(64-36)

√28 or 2√7

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โˆ™ 2011-03-16 03:15:42
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A polynomial of degree zero is a constant term

The grouping method of factoring can still be used when only some of the terms share a common factor A True B False

The sum or difference of p and q is the of the x-term in the trinomial

A number a power of a variable or a product of the two is a monomial while a polynomial is the of monomials

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Q: What is the distance between 5 -2 and -3 4?
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How can you find the distance between two numbers on a number line?

Just subtract the lowest number from the greatest number. For example, the distance between 3 and 8, is 8 - 3 = 5 units, the distance between -2 and 3, is 3 - (-2) = 3 + 2 = 5 units, the distance between -4 and -2, is -2 - (-4) = -2 + 4 = 2 units.


Find the distance between (-4 2) and (-7 -6). in units?

The distance between the points of (4, 3) and (0, 3) is 4 units


What is the distance between the points -4 3 and 3 -1?

Points: (-4, 3) and (3, -1) Distance: (3--4)2+(-1-3)2 = 65 and the square root if this is the distance which is just over 8


What is the distance between two points -3 7 and -6 4?

(-3-(-6))2 + (7-4)2 = 18 and the square root of this is the distance between the two points


What is the distance between (3 5) and (3 -4)?

It is the square root of (-3-0)2+(-4-0)2 = 5


What is the distance between -2 4 and 1 -2?

What is the distance between (4, -2) and (-1,6)?


What is the distance between the origin -3 and -4?

It is the square root of (-3-0)2+(-4-0)2 = 5


What is the distance between points 1 2 and 4 -1?

Use Pythagoras to find the distance between two points (x0,.y0) and (x1, y1): distance = √(change_in_x² + change_in_y²) → distance = √((x1 - x0)² + (y1 - y0)²) → distance = √((4 - 1)² + (-1 -2)²) → distance = √(3² + (-2)²) → distance = √(9 + 9) → distance = √18 = 3 √2


What is the distance between 4 -2 and -1 6?

What is the distance between (4, -2) and (-1,6)?


What is the distance between points 2 4 and 6 3?

Using Pythagoras: distance = √(difference_in_x^2 + difference_in_y^2) = √((6 - 2)^2 + (3 - 4)^2) = √(16 + 1) = √17 ≈ 4.12


What is the distance between 1 and -3 on a number line?

4


What is the distance between the points named by (2 3) and (2 7) on the coordinate plane?

Points: (2, 3) and (2, 7) Distance works out as: 4 units

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