A: 11x = 5y + 80
B: 9x - 15y = 120
A: 11x - 5y = 80
B: 9x - 15y = 120
A: 11x - 5y = 80
B: 3x - 5y = 40
A - B: 8x = 40
x = 5
Now we can plug that value of x into one of the original equations to solve for y:
11(5) - 5y = 80
55 - 5y = 80
-5y = 25
y = -5
By elimination: x = 3 and y = 0
y=16 x= -4
16
(2,-2)
Solving by the elimination method: x = 7 and y = 2
By elimination: x = 3 and y = 0
y=16 x= -4
16
(2,-2)
Solving by the elimination method: x = 7 and y = 2
The elimination method only works with simultaneous equations, hence another equation is needed here for it to be solvable.
Yes and it works out that x = 3 and y = 4
Solving these simultaneous equations by the elimination method:- x = 1/8 and y = 23/12
Solving the above simultaneous equations by means of the elimination method works out as x = 2 and y = 3
Double first equation: 2x + 2y = 4 Subtract this from second equation giving 5y = 5 so y = 1 and x = 1
x = 5, y = -2
Usually elimination is used on two equations and is called linear combination. You could solve for "y." That is customary. 2x+3y=1 3y=-2y+1 y=(-2/3)x+1/3