Q: What is the equation for a circle with a center of 0 0 and a radius of 9?

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x2 + y2 = 81

x2+(y - 2)= 121

(x-0)² + (y-0)² = r²

center (3,0) radius 12 So the equation is (x-3)^2 + y^2 = 144 → y^2 + x^2 - 6x - 135 = 0 in general a circle of radius r centered at (h, k) has the equation: (x - h)^2 + (y - k)^2 = r^2

A circle centre (0, 0) and radius r has equation x² + y² = r² The circle x² + y² = 36 has: r² = 36 → radius = 6

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The equation of the circle is: x^2 + y^2 = 81

x2 + y2 = 81

x2+(y - 2)= 121

(x - 0)2 + (y - 0)2 = 49

(x-0)² + (y-0)² = r²

The equation is: (x -0)^2 +(y -2)^2 = 121

(x-3)2+y2=144

The general equation of a circle is given by the formula(x - h)2 + (x - k)2 = r2, where (h, k) is the center of the circle, and r its radius.Since the center of the circle is (0, 0), the equation reduces tox2 + y2 = r2So that the equation of our circle is x2 + y2 = 36.

x2+y2+4x+2y+3=0(x+2)2 + (Y+2.5)2 = 3This is the equation of circle with center at (-2,-2.5) with radius 3.5

center (3,0) radius 12 So the equation is (x-3)^2 + y^2 = 144 → y^2 + x^2 - 6x - 135 = 0 in general a circle of radius r centered at (h, k) has the equation: (x - h)^2 + (y - k)^2 = r^2

A circle centre (0, 0) and radius r has equation x² + y² = r² The circle x² + y² = 36 has: r² = 36 → radius = 6

Equation of a circle when its centre is at (0, 0): x^2 + y^2 = radius^2 Equation of a circle when its centre is at (a, b): (x-a)^2 + (y-b)^2 = radius^2