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What is the equation for a circle with a center of 0 and a radius of 9?
x2 + y2 = 81
What is the equation for a circle with a center of (0 2) and a radius of 11?
The equation of a circle is given by the formula ((x - h)^2 + (y - k)^2 = r^2), where ((h, k)) is the center and (r) is the radius. For a circle with a center at ((0, 2)) and a radius of 11, the equation becomes ((x - 0)^2 + (y - 2)^2 = 11^2). Simplifying this, the equation is (x^2 + (y - 2)^2 = 121).
What is the equation for a circle with a center of 0 2 and a radius of 11?
x2+(y - 2)= 121
What is the equation of a circle whose center is at the origin and whose radius is 16?
(x-0)² + (y-0)² = r²
How To find the standard equation for a circle centered at the origin we use the distance formula since the radius measures?
To find the standard equation for a circle centered at the origin, we use the distance formula to define the radius. The equation is derived from the relationship that the distance from any point ((x, y)) on the circle to the center ((0, 0)) is equal to the radius (r). Thus, the standard equation of the circle is given by (x^2 + y^2 = r^2). Here, (r) is the radius of the circle.
What is the equation for a circle with a center of (0 0) and a radius of 9?
The equation of the circle is: x^2 + y^2 = 81
What is the equation for a circle with a center of 0 and a radius of 9?
x2 + y2 = 81
What is the equation for a circle with a center of (0 2) and a radius of 11?
The equation of a circle is given by the formula ((x - h)^2 + (y - k)^2 = r^2), where ((h, k)) is the center and (r) is the radius. For a circle with a center at ((0, 2)) and a radius of 11, the equation becomes ((x - 0)^2 + (y - 2)^2 = 11^2). Simplifying this, the equation is (x^2 + (y - 2)^2 = 121).
What is the equation for a circle with a center of 0 2 and a radius of 11?
x2+(y - 2)= 121
What is the equation of a circle whose center is at the origin and whose radius is 16?
(x-0)² + (y-0)² = r²
What is the equation of a circle with its center at the origin and radius 7?
(x - 0)2 + (y - 0)2 = 49
What is this equation for a circle with a center of (02) and a radius of 11?
The equation is: (x -0)^2 +(y -2)^2 = 121
What is the equation for a circle with a center of (3 0) and a radius of 12?
(x-3)2+y2=144
If a circle is centered at the origin and the length of its radius is 6 What is the circle's equation?
The general equation of a circle is given by the formula(x - h)2 + (x - k)2 = r2, where (h, k) is the center of the circle, and r its radius.Since the center of the circle is (0, 0), the equation reduces tox2 + y2 = r2So that the equation of our circle is x2 + y2 = 36.
Find the center and radius of the circle with this equation x2 plus y2 plus x equals 0?
x2+y2+4x+2y+3=0(x+2)2 + (Y+2.5)2 = 3This is the equation of circle with center at (-2,-2.5) with radius 3.5
How To find the standard equation for a circle centered at the origin we use the distance formula since the radius measures?
To find the standard equation for a circle centered at the origin, we use the distance formula to define the radius. The equation is derived from the relationship that the distance from any point ((x, y)) on the circle to the center ((0, 0)) is equal to the radius (r). Thus, the standard equation of the circle is given by (x^2 + y^2 = r^2). Here, (r) is the radius of the circle.
What is the equation for a circle with a center of 3 0 and a radius of 12?
center (3,0) radius 12 So the equation is (x-3)^2 + y^2 = 144 → y^2 + x^2 - 6x - 135 = 0 in general a circle of radius r centered at (h, k) has the equation: (x - h)^2 + (y - k)^2 = r^2
