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Q: What is the equation for a circle with a center of 0 and a radius of 9?

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The equation of the circle is: x^2 + y^2 = 81

x2 + y2 = 64

x^2 + y^2 = 81

x2+(y - 2)= 121

(x-0)² + (y-0)² = r²

(x - 0)2 + (y - 0)2 = 49

The equation is: (x -0)^2 +(y -2)^2 = 121

(x-3)2+y2=144

The general equation of a circle is given by the formula(x - h)2 + (x - k)2 = r2, where (h, k) is the center of the circle, and r its radius.Since the center of the circle is (0, 0), the equation reduces tox2 + y2 = r2So that the equation of our circle is x2 + y2 = 36.

x2+y2+4x+2y+3=0(x+2)2 + (Y+2.5)2 = 3This is the equation of circle with center at (-2,-2.5) with radius 3.5

A circle centre (0, 0) and radius r has equation x² + y² = r² The circle x² + y² = 36 has: r² = 36 → radius = 6

Equation of a circle when its centre is at (0, 0): x^2 + y^2 = radius^2 Equation of a circle when its centre is at (a, b): (x-a)^2 + (y-b)^2 = radius^2

center (3,0) radius 12 So the equation is (x-3)^2 + y^2 = 144 → y^2 + x^2 - 6x - 135 = 0 in general a circle of radius r centered at (h, k) has the equation: (x - h)^2 + (y - k)^2 = r^2

The center of the circle is at (0, 0) and its radius is the square root of 1 which is 1

The centre is (3,-1) and the radius is sqrt(10).

x2 + y2 = 25 A circle with centre (xo, yo) and radius r has equation: (x - xo)2 + (y - yo)2 = r2 So with centre the origin (0, 0) and radius 5 cm, the circle has equation: (x - 0)2 + (y - 0)2 = 52 ⇒ x2 + y2 = 25

The equation of a circle with center (0,2) and radius r is x^2+(y-2)^2=r^2 Since it passes through (0,0) (the origin) 0^2+(0-2)^2=r^2 r^2=4 The equation of the circle is x^2+(y-2)^2=4

You need to think of that equation in terms of the classic definition of a circle: (x - a)2 + (y - b)2 = r2 where a and b are the center of the circle, x and y are any point on it's circumference, and r is it's radius. In the case of the circle you're looking at: x2 + y2 = 16 You can re-express it like this: (x - 0)2 + (y - 0)2 = 42 So that circle has a center at the point (0, 0), and a radius of 4.

The general formula: (x - h)^2 + (y - k)^2 = r^2, where (h, k) is the center and r is the radius. So the required equation of the circle is: (x - -4)^2 + (y - 0)^2 = 10^2 (x + 4)^2 + y ^2 = 100

Any value from 0 to the magnitude of the radius.

Equation of circle: x^2 +y^2 -4x -6y -3 = 0 Completing the squares: (x-2)^2 +(y-3)^2 = 16 square units Therefore center of circle is at (2, 3) and its radius is 4 units

Center of circle: (2, 5) Point of contact with the x axis: (2, 0) Distance from (2, 5) to (2, 0) equals 5 which is the radius of the circle Equation of the circle: (x-2)^2 +(y-5)^2 = 25

Equation of circle: x^2 +y^2 -10x +6y -15 = 0 Completing the squares: (x-5)^2 +(y+3)^2 = 49 square units Therefore center of circle is at (5, -3) and its radius is 7 units

(x - 4)2 + (y - 0)2 = 102 or x2 - 8x + 16 + y2 = 100 or x2 - 8x + y2 - 84 = 0

Equation of circle: x^2 +y^2 -8x -16y -209 = 0 Completing the squares: (x-4)^2 +(y-8)^2 = 289 Radius of circle: 17 Center of circle: (4, 8) Point of contact: (21, 8) Slope of radius: 0 Slope of tangent line: 0 Equation of tangent line: x = 21 which means it touches the circle at (21, 0) which is a straight vertical line parallel to the y axis