5 + n = 20
======== ( and, in this case, means addition and is means equal )
The sum of n and 5 is n+ 5
Call the two numbers required m and n. Then from the problem statement, m = 25 - n (equation 1) and mn = 100 (equation 2). Substitute the expression for m in equation 1 into equation 2 to produce n(25 - n) = 100. Multiply out the left side to produce 25 n - n2 = 100. Multiply this equation by -1 and collect all terms on one side to produce n2 - 25n -100 = 0 (equation 3). Equation 3 factors into (n -20)(n-5) = 0, which is true when n = 20 or n = 5. From equation 1 again, this means m = 5 or 20 respectively. Therefore, the two numbers required are 5 and 20. Check: 5 + 20 = 25; 5 X 20 = 100.
To find the sum of interior angles for any N-sided polygon = N*180° - 360°Solve the equation: N*180° - 360° = 3240°, for N, and N = 20, so a 20 sided polygon will have sum of interior angles = 3240°, and if it is a regular polygon, then each angle = 162°
The sum from 1 to n is n*(n+1)/2In this case that mean 20*21/2 = 210The sum from 1 to n is n*(n+1)/2In this case that mean 20*21/2 = 210The sum from 1 to n is n*(n+1)/2In this case that mean 20*21/2 = 210The sum from 1 to n is n*(n+1)/2In this case that mean 20*21/2 = 210
n + 2 = 10
The appropriate equation is: 5*(-3 + N) = -20
9*n + 28 >= -20.
For this question we can say Nita = N and Joe = J and set up an equation:equation 1: N = J + 10 and equation 2: 20 = J + Nwe can solve for J using equation 1 inside of equation 2:20 = (J + 10) + J20 - 10 = 2*JTherefore: J = (20 - 10)/2 = 5Now we solve for N by plugging in 5 for J in equation 1:N = 5 + 10 = 15Nita is 15 and Joe is 5
The sum of n and 5 is n+ 5
find the sum and product of the roots of 8×2+4×+5=0
Call the two numbers required m and n. Then from the problem statement, m = 25 - n (equation 1) and mn = 100 (equation 2). Substitute the expression for m in equation 1 into equation 2 to produce n(25 - n) = 100. Multiply out the left side to produce 25 n - n2 = 100. Multiply this equation by -1 and collect all terms on one side to produce n2 - 25n -100 = 0 (equation 3). Equation 3 factors into (n -20)(n-5) = 0, which is true when n = 20 or n = 5. From equation 1 again, this means m = 5 or 20 respectively. Therefore, the two numbers required are 5 and 20. Check: 5 + 20 = 25; 5 X 20 = 100.
To find the sum of interior angles for any N-sided polygon = N*180° - 360°Solve the equation: N*180° - 360° = 3240°, for N, and N = 20, so a 20 sided polygon will have sum of interior angles = 3240°, and if it is a regular polygon, then each angle = 162°
To calculate the sum of the numbers 1 to n, the formula is: sum = n(1 + n) / 2 So, an equation to find the sum of the integers 1 to 2010 is: sum = 2010 x (1 + 2010) / 2
If you were trying to find 1+2+3+4+5+...+(n-1)+n the formula would be (n*(n+1))/2
The sum from 1 to n is n*(n+1)/2In this case that mean 20*21/2 = 210The sum from 1 to n is n*(n+1)/2In this case that mean 20*21/2 = 210The sum from 1 to n is n*(n+1)/2In this case that mean 20*21/2 = 210The sum from 1 to n is n*(n+1)/2In this case that mean 20*21/2 = 210
N+5=n+5
The sum is 3420 as the equation for every regular polygon is (n-2)*180 when n is number of sides