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What is the equation in its general form that passes through - 2 -3 and is perpendicular to 4x plus 3y -5 equals 0 showing work?
Wiki User
∙ 8y ago
If: 4x+3y-5 = 0 then y = -4/3x+5/3
Perpendicular slope: 3/4
Perpendicular equation: y--3 = 3/4(x--2) => 4y+12 = 3x+6 => 4y = 3x-6
In its general form: 3x-4y-6 = 0
Wiki User
∙ 8y ago
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What is the equation of a line that passes through 3 -4 and is perpendicular to 5x -2y equals 3 on the Cartesian plane?
Perpendicular slope: -2/5 Perpendicular equation: y--4 = -2/5(x-3) => 5y--20 = -2x-3 => 5y = -2x-14 Perpendicular equation in its general form: 2x+5y+14 = 0
What is the equation passing through the point 3 -4 which is perpendicular to the line 5x -2y equals 3?
Known equation: 5x-2y = 3 or y = 5/2x -3/2 Slope of known equation: 5/2 Slope of perpendicular equation: -2/5 Perpendicular equation: y- -4 = -2/5(x-3) => 5y =-2x-14 Perpendicular equation in its general form: 2x+5y+14 = 0
What is the equation of a straight line that cuts through the middle of the points of -1 3 and -2 -5 at right angles on the Cartesian plane showing work?
The equation will be a perpendicular bisector equation of the given points:- Points: (-1, 3) and (-2, -5) Midpoint: (-3/2, -1) Slope: 8 Perpendicular slope: -1/8 Perpendicular equation: y--1 = -1/8(x--3/2) => y = -1/8x-3/16-1 Therefore the perpendicular bisector equation is: y = -1/8x -19/16
What is the equation of the line that it is perpendicular to y7x-3 and passes through the origin?
If you mean 7 = 7x-3 then the perpendicular slope is -1/7 and the equation is y = -1/7x
What is the equation of a line that passes through the point 0 -3 and is perpendicular to a line with a slope of 4?
Perpendicular slope: -1/4 Perpendicular equation: y-0 = -1/4(x-3) => y = -0.25x+3
What is the equation of the line in its general form that passes through -2 -3 and is perpendicular to the equation of 4x plus 3y -5 equals 0?
It works out in its general form as: 3x-4y-6 = 0
What is the equation of a line that passes through 3 -4 and is perpendicular to 5x -2y equals 3 on the Cartesian plane?
Perpendicular slope: -2/5 Perpendicular equation: y--4 = -2/5(x-3) => 5y--20 = -2x-3 => 5y = -2x-14 Perpendicular equation in its general form: 2x+5y+14 = 0
What is the equation of the line passing through 3 -4 and it is perpendicular to the line 5x -2y equals 3?
Known equation: 5x -2y = 3 or y = 5/2x -3/2 Slope of equation: 5/2 Slope of perpendicular equation: -2/5 Perpendicular equation: y --4 = -2/5(x -3) => 5y = -2x -14 Perpendicular equation in its general form: 2x+5y+14 = 0
Which equation represents a line that passes through the point (5, 5) and is perpendicular to the line x + 2y = 10?
General formula
What is the equation of the line passing through -2 -3 that is at right angles to the equation 4x plus 3y -5 equals 0 on the Cartesian plane?
The equation will be perpendicular to the given equation and have a slope of 3/4:- Perpendicular equation: y--3 = 3/4(x--2) => 4y--12 = 3x--6 => 4y = 3x-6 Perpendicular equation in its general form: 3x-4y-6 = 0
What is the equation passing through the point 3 -4 which is perpendicular to the line 5x -2y equals 3?
Known equation: 5x-2y = 3 or y = 5/2x -3/2 Slope of known equation: 5/2 Slope of perpendicular equation: -2/5 Perpendicular equation: y- -4 = -2/5(x-3) => 5y =-2x-14 Perpendicular equation in its general form: 2x+5y+14 = 0
What is in its general form the perpendicular bisector equation cutting through the line segment of -7 -3 and -1 -4?
Points: (-7, -3) and (-1, -4) Slope: -1/6 Perpendicular slope: 6 Mid-point (-4, -3.5) Equation: y - -3.5 = 6(x - -4) => y = 6x+20.5 Perpendicular bisector equation in its general form: 6x -y+20.5 = 0
What is the equation of a straight line that cuts through the middle of the points of -1 3 and -2 -5 at right angles on the Cartesian plane showing work?
The equation will be a perpendicular bisector equation of the given points:- Points: (-1, 3) and (-2, -5) Midpoint: (-3/2, -1) Slope: 8 Perpendicular slope: -1/8 Perpendicular equation: y--1 = -1/8(x--3/2) => y = -1/8x-3/16-1 Therefore the perpendicular bisector equation is: y = -1/8x -19/16
What is the perpedicular bisector equation of a line that cuts through the line of h plus k and 3h minus 5k showing key stages of work?
Points: (h, k) and (3h, -5k) Slope: -3k/h Perpendicular slope: h/3k Midpoint: (2h, -2k) Perpendicular equation: y--2k = h/3k(x-2h) Multiply all terms by 3k: 3ky--6k2 = h(x-2h) Equation in terms of 3ky = hx-2h2-6k2 Perpendicular bisector equation in its general form: hx-3ky-2h2-6k2 = 0
What in its general form is the perpendicular bisector equation passing through the line segment of h k and 3h -5k showing key stages of your work?
8
What is the equation of the line that it is perpendicular to y7x-3 and passes through the origin?
If you mean 7 = 7x-3 then the perpendicular slope is -1/7 and the equation is y = -1/7x
What is the equation of the line that passes through the point of 3 -4 and is perpendicular to the line 5x -2y equals 3?
Known equation: 5x -2y=3 => y=5/2x -1.5 Slope of equation: 5/2 Perpendicular slope: -2/5 Perpendicular equation: y--4=-2/5(x-3) => 5y--20=-2x+6 => 5y=-2x-14 Therefore the perpendicular in its general form is: 2x+5y+14 = 0
