the slope of a line is 9/5 the y intercept is -4, express the equation of the line in point slope form
Rewriting the equation 3x + y = 15 gives y = 15 - 3xThe slope of this and any parallel line is the x multiple, which in this case is -3
36x-9y = 15 -9y = -36x+15 y = 4x-5/3 in slope intercept form
3X + 5Y = 155Y = -3X + 15Y = (-3/5)X + 3The slope of this line is -3/5.The slope of a line perpendicular to it is 5/3.
Points: (-2, 4) and (-4, 8) Midpoint: (-3, 6) Slope: -2 Perpendicular slope: 1/2 or 0.5 Perpendicular bisector equation: y-6 = 0.5(x--3) meaning y = 0.5x+7.5
f(6) = 3 This gives us the point (x1, y1) = (6, 3), andf(9) = 15, gives us the point (x2, y2) = (9, 15).Since we have two points, we can write the point slope intercept form of the equation of the line passing through these two points. To do this we need to find the slope m of the line. So,slope = m = (y2 - y1)/(x2 - x1) = (15 - 3)/(9 - 6) = 12/3 = 4(y - y1) = m(x - x1) the point slope intercept form(y - 3) = 4(x - 6)y - 3 = 4x - 24 add 3 to both sidesy = 4x - 3 subtract y to both sides0 = 4x - y -3 or4x - y -3 = 0
Without the inclusion of an equality sign and not knowing the plus or minus values of the given terms it can't be considered to be a straight line equation
The slope of the line that represents the graph of that equation is 15.
15
If the point is (-6, 3) and the slope is 2 then the equation is: y = 2x+15
If you mean a slope of 2/5 and the point (-15, 12) then equation is 5y = 2x+90
Equation of given line: 3x + y = 15 or y = -3x + 15 Slope of given line = coefficient of x = -3 Slope of perperndicular = -1/(slope of given line) = -1 / (-3) = 1/3
-5
Rewriting the equation 3x + y = 15 gives y = 15 - 3xThe slope of this and any parallel line is the x multiple, which in this case is -3
If the point is (6, 3) and the slope is -1/3 then the equation works out as 3y = -x+15
I'm assuming here that this line is a straight line. If so, it has the general equation y=mx+c (where m= the gradient/slope and c is the intercept). Substituting in the values provided in the question, we yield; 15= (9x9)+c We then solve and rearrange; 15=81+c 15-81=c -66=c. Therefore, the slope intercept is -66
this is an equation of a line. it has a slope of 4/3 and a y-intercept of 5
Slope: 2/3 Point: (9, 11) Equation: 3y = 2x+15