3x - y = 3 or
y = 3x - 3
This is an equation of a line in the slope-intercept form, where the y-intercept is -3.So that the line passes through the point (0, -3).
If we substitute 1 and -1 for x into the given equation, we can find two other points, which are (-1, -6) and (1, 0).
Now you are able to draw the line that passes through these three points, which is the line represented by the given equation.
That equals 2xy + 3y which factors to y(2x + 3)
No translation will invert a quadratic graph.
2x + 5y = 2-3x - y = -3from the second equation:-y = -3 + 3xy = 3 - 3xsubstitute this value in the first equation:2x + 5(3-3x) = 22x + 15 - 15x = 2-13x + 15 = 2-13x = 2 - 15-13x = -13so, x = 1Now, solve for y :y = 3 - 3xy = 3 - 3 (1)y = zero
2(2)2 + 3(2)(- 4) - 4(- 4)2 8 - 24 - 64 = - 80 ======
The graph of is shifted 3 units down and 2 units right. Which equation represents the new graph?
2x^2+3xy-4y2(4)+3(2)(-4)-(4)(-4)8-24+16=0
They are: (3, 1) and (-11/5, -8/5)
That equals 2xy + 3y which factors to y(2x + 3)
3xy
No translation will invert a quadratic graph.
x = -1 y = 2 2x3 - 3xy = 2 (-1)3 - 3(-1)(2) = 2 (-1) - (-6) = -2 + 6 = 4 Suggestion: Please be careful around problems like this until you have some more experience.
M=3 because y+y+y= 3xY and MY= MxY
3
First, reflect the graph of y = x² in the x-axis (line y = 0) to obtain the graph of y = -x²; then second, shift it 3 units up to obtain the graph of y = -x² + 3.
-2.25
2x + 5y = 2-3x - y = -3from the second equation:-y = -3 + 3xy = 3 - 3xsubstitute this value in the first equation:2x + 5(3-3x) = 22x + 15 - 15x = 2-13x + 15 = 2-13x = 2 - 15-13x = -13so, x = 1Now, solve for y :y = 3 - 3xy = 3 - 3 (1)y = zero
The graph is a horizontal line at y=3