Since any 2 points determine 1 line, take 2 of the points and find the equation of the line drawn thru these 2 points.
Substitute the x and y of the either point into the equation and find the y-intercept (b)
Then, substitute the x and y of the 3rd point into the equation and see if the both sides of the equation are =.
(y2-y1) ÷ (x2 - x1) = slope
y = slope * x + b
Point # 1 = (6, 5)
Point # 2 = (10, 25)
Point # 3 = (12, 30)
Point # 4 = (12, 35)
(y2 - y1) ÷ (x2 - x1) = slope
(25 - 5) ÷ (10 - 6) = slope
(20) ÷ (4) = slope
Slope = 5
y = m * x + b
y = 5 * x + b
Substitute the x and y of the point (6, 5) into the equation and find the y-intercept (b)
y = 5 * x + b
5 = 5 * 6 + b
5 = 30 + b
b = -25
y = 5 * x - 25
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Check your points
Point # 1 = (6, 5)
5 = 5 * 6 - 25
5 = 30 - 25 OK
.
Point # 2 = (10, 25)
25 = 5 * 10 - 25
25 = 5 * 10 - 25 OK
.
Then, substitute the x and y of the 3rd point into the equation and see if the both sides of the equation are
Point # 3 = (12, 30)
.
y = 5 * x - 25
30 = 5 * 12 - 25
30 = 60 - 25 = 35
Point # 3 = (12, 30) is not on the line
.
.
Point # 4 = (12, 35)
35 = 5 * 12 - 25
35 = 60 - 25 =35
Point # 4 = (12, 35) is on the line
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Any three points that are non-collinear (not on the same line) will determine a plane.
no.
8 collinear points determine 28 unique line segments
I dont think that "If four points are collinear they are also coplaner," is the same thing as "If four points are coplaner they are also collinear,". The definition of collinear is at least three points on the same line. To define a plane is to have threenoncollinear points.
Not enough information. Collinear means the points are on the same line. If you have any three points, they may, or may not, be on the same line.