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What is the equation of the parabola when the vertex is (3 2) and the focus is (5 2)?
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What is the equation of a parabola with the vertex of 2 -1?
3
What could be the equation of the parabola centered at the vertex?
f(x)=x^2
The co-ordinates of the focus of Parabola x minus 3 power 2 is equal to 4 y minus 2 is Answer is 3 3 how?
The standard equation for an upward opening parabola with its vertex at (f,g) is (x - f)2 = 4c(y - g), where c is the focal length, that is the distance of the focus from the vertex. Putting the equation shown in this form we have :- (x - 3)2 = 4 * 1(y - 2) . . . thus c = 1 The vertex is at (3,2) and as the focal length is 1 (and this is positive) then the coordinates of the focus are (3, [2 + 1]) = (3,3).
A parabola has a vertex at -3 -2 what is its equation?
-1
What is the standard form of the equation of the parabola with vertex 00 and directrix y4?
Assuming the vertex is 0,0 and the directrix is y=4 x^2=0
The vertex of the parabola below is at the point (-4-2) which equation below could be one for parabola?
-2
The vertex of this parabola is at -2 -3 When the y-value is -2 the x-value is -5 What is the coefficient of the squared term in the parabola's equation?
The vertex of this parabola is at -2 -3 When the y-value is -2 the x-value is -5. The coefficient of the squared term in the parabola's equation is -3.
The vertex of the parabola below is at the point 4 -1 which equation be this parabola's equation?
5
What is the equation of a parabola with the vertex of 2 -1?
3
What is the equation of a parabola with vertex at 1 -3 and focus at 2 -3?
For a parabola with an axis of symmetry parallel to the x-axis, the equation of a parabola is given by: (y - k)² = 4p(x - h) Where the vertex is at (h, k), and the distance between the focus and the vertex is p (which can be calculated as p = x_focus - x_vertex). For the parabola with vertex (1, -3) and focus (2, -3) this gives: h = 1 k = -3 p = 2 - 1 = 1 → parabola is: (y - -3)² = 4×1(x - 1) → (y + 3)² = 4(x - 1) This can be expanded to: 4x = y² + 6y + 13 or x = (1/4)y² + (3/2)y + (13/4)
What could be the equation of the parabola centered at the vertex?
f(x)=x^2
What are the coordinates of the vertex of the parabola described by the equation below?
The coordinates will be at the point of the turn the parabola which is its vertex.
What is the focus of a parabola?
The focus of a parabola is a fixed point that lies on the axis of the parabola "p" units from the vertex. It can be found by the parabola equations in standard form: (x-h)^2=4p(y-k) or (y-k)^2=4p(x-h) depending on the shape of the parabola. The vertex is defined by (h,k). Solve for p and count that many units from the vertex in the direction away from the directrix. (your focus should be inside the curve of your parabola)
The co-ordinates of the focus of Parabola x minus 3 power 2 is equal to 4 y minus 2 is Answer is 3 3 how?
The standard equation for an upward opening parabola with its vertex at (f,g) is (x - f)2 = 4c(y - g), where c is the focal length, that is the distance of the focus from the vertex. Putting the equation shown in this form we have :- (x - 3)2 = 4 * 1(y - 2) . . . thus c = 1 The vertex is at (3,2) and as the focal length is 1 (and this is positive) then the coordinates of the focus are (3, [2 + 1]) = (3,3).
What is an equation of the parabola in vertex form that passes through (13 8) and has vertex (3 2).?
please help
A parabola has a vertex at -3 -2 what is its equation?
-1
The vertex of the parabola below is at the point -3 -5 Which of the equations below could be the equation of this parabola?
2
