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Q: What is the factorization of x2 24x 41?

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x3 - 10x2 + 24x = x(x2 - 10x + 24) = x(x - 6)(x - 4).

3x3-18x2+24x=3x(x2-6x+8)=3x(x-4)(x-2)

3X3 + 6X2 - 24X3X(X2 + 2X - 8)3X(X + 4)(X - 2)================assuming that last term was - 24X

x2+24x+144 = 9 x2+24x+144-9 = 0 x2+24x+135 = 0 (x+9)(x+15) = 0 x = -9 or x = -15

x3 - 10x2 + 24x = x(x2 - 10x + 24) = x(x2 - 4x - 6x + 24) = x[ x(x - 4) - 6(x - 4) ] = x(x - 6)(x - 4)

Im assuming you mean x2 (x squared). This equation will be a quadratic. so... x2+144=-24x subtract -24x from itself and the other side -24x -24x ----------------- x2-24x+144=0 now break it down even further (x-12)(x-12)=0 Now you solve the "mini-equations" x-12=0 x-12=0 +12 +12 +12 +12 --------------------------- x=12 or x=12 hope it helps!!!

2x2-24x-320 in simpler terms is 2(x2-12x-160) 2(x2-12x-160) =2(x-20)(x+8)

6x(1+4)

144

x(x - 4)(x - 6)

3x(x + 4)(x - 2)

205 Factorization: 5*41

4(x2 - 6x + 13)

41 is prime.

Given: x2 + 10x - 16 Let: x2 + 10x - 16 = 0 x2 + 10x - 16 = 0 ∴ x2 + 10x + 25 = 16 + 25 ∴ (x + 5)2 = 41 ∴ x = -5 ± √41 ∴ x2 + 10x - 16 = (x + 5 + √41)(x + 5 - √41)

(3x - 8)(8x + 5)

x(x + 4)(x + 6)

Hard to interperet the question here. x2-24x factorizes into x(x-24) The 70-30 is just 40 which has factors 5,2,2,2. Suggest rewriting the question, distinguishing between x and the multiplication sign.

3x3 + 6x2 - 24x = 3x(x2 + 2x - 8) = 3x(x2 + 4x - 2x - 8) = 3x[ x(x + 4) - 2(x + 4) ] = 3x(x - 2)(x + 4)

26

None. 41 is a prime number.

The prime factorization of 287 is 7*41.

x2 - 41 cannot be factorised.

2 x 2 x 2 x2 x2 x2 x 3 x 11

x2 - 21x = 72x2 - 21x - 72 = 0(x - 24) (x + 3) = 0x = 24x = -3