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35 minus 4 differences, ie 4 x 6 so first term is 11 and progression runs 11,17,23,29,35...

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Q: What is the first term of an arithmetic sequence with a common difference of 6 and a fifth term of 35?
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The first term is 4 and the common difference is 3. the fifth term of this sequence is?

The nth term of a arithmetic sequence is given by: a{n} = a{1} + (n - 1)d → a{5} = a{1} + (5 - 1) × 3 → a{5} = 4 + 4 × 3 = 16.


What is the fifth term of the arithmetic sequence 7 4 1?

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Can you explain a pattern in which 14 is the fifth term in a sequence of ten numbers?

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The nth term for that arithmetic progression is 4n-1. Therefore the next term (the fifth) in the sequence would be (4x5)-1 = 19.


The first term of an arithmetic sequence 7 the tenth term is 34 what is the fifth term?

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What is the meaning of fourth?

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How can you find the first term of an arithmetic sequence if you know the third and fifth terms?

Suppose A is the first term and R is common difference. Then, if t(n) is the nth term, t(n) = A + n*R Then t(5) = A + 5R and t(3) = A + 3R so that t(5) - t(3) = 2R Now t(1) = A + R = A + 3R - 2R (since R = 3R - 2R) So t(1) = t(3) - 2R You were given t(3) and have calculated 2R above, so can work out t(1).