You.... have to apply this formula! n(n+1)/2 and n is the no. of terms
The formula for the sum of an arithmetic series is given by ( S_n = \frac{n}{2} (a + l) ) or ( S_n = \frac{n}{2} (2a + (n - 1)d) ), where ( S_n ) is the sum of the first ( n ) terms, ( a ) is the first term, ( l ) is the last term, ( d ) is the common difference, and ( n ) is the number of terms. The first formula uses the first and last terms, while the second uses the first term and the common difference.
The given series appears to follow a pattern where each term can be expressed in the form of a quadratic sequence. The nth term can be represented as ( a_n = n(3n - 2) ). To find the sum of the first n terms, ( S_n ), we can derive it from the formula for the sum of a quadratic sequence, leading to ( S_n = \frac{n}{6}(n + 1)(n + 2) ). Thus, the sum to n terms of the series is given by this formula.
a+a*r+a*r^2+...+a*r^n a = first number r = ratio n = "number of terms"-1
It is not possible to answer this question without information on whether the terms are of an arithmetic or geometric (or other) progression, and what the starting term is.
Permutation Formula A formula for the number of possible permutations of k objects from a set of n. This is usually written nPk . Formula:Example:How many ways can 4 students from a group of 15 be lined up for a photograph? Answer: There are 15P4 possible permutations of 4 students from a group of 15. different lineups
The formula for the sum of the first n terms of an arithmetic progression is Sn = n/2 * (a + l), where Sn is the sum, n is the number of terms, a is the first term, and l is the last term.
You.... have to apply this formula! n(n+1)/2 and n is the no. of terms
The formula for the sum of an arithmetic series is given by ( S_n = \frac{n}{2} (a + l) ) or ( S_n = \frac{n}{2} (2a + (n - 1)d) ), where ( S_n ) is the sum of the first ( n ) terms, ( a ) is the first term, ( l ) is the last term, ( d ) is the common difference, and ( n ) is the number of terms. The first formula uses the first and last terms, while the second uses the first term and the common difference.
The formula for calculating the Gauss sum from 1 to 100 is n(n1)/2, where n is the number of terms in the sequence.
RAMANUJANRAMANUJAN
The general electronic configuration of p block elements is ns2 np1-6. This means that the outermost electron shell of p block elements contains electrons in either the np1, np2, np3, np4, np5, or np6 orbitals.
a+a*r+a*r^2+...+a*r^n a = first number r = ratio n = "number of terms"-1
t(1) = 1t(2) = 1t(n) = t(n-2) + t(n-1) for n = 3, 4, 5, ...that is, the first and second terms are 1. After that, each term is the sum of the previous two terms.
Hey guys....There is no correct simple general formula for sum to n terms of the series1+1/2+1/3+1/4+ ............. + 1/nThe following expression is relatively a very good approximation.S = ln(n + 0.5) + 0.5772 + 0.03759/(n*n + 1.171)Deviation from the actual value fluctuates but remains relatively low.
It is not possible to answer this question without information on whether the terms are of an arithmetic or geometric (or other) progression, and what the starting term is.
The formula to find the sum of a geometric sequence is adding a + ar + ar2 + ar3 + ar4. The sum, to n terms, is given byS(n) = a*(1 - r^n)/(1 - r) or, equivalently, a*(r^n - 1)/(r - 1)