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You.... have to apply this formula! n(n+1)/2 and n is the no. of terms
a+a*r+a*r^2+...+a*r^n a = first number r = ratio n = "number of terms"-1
It is not possible to answer this question without information on whether the terms are of an arithmetic or geometric (or other) progression, and what the starting term is.
The simplest formula is: t(n) = 2n + 5 for n = 1, 2, 3, ... However, that is not the only formula; there are infinitely many polynomial formulae that can be found that give those five terms first, but for the 6th or further terms vary.
Assuming each term is 3 MORE than the previous term t(n) = -13 + 3*n where n = 1, 2, 3, ...