You.... have to apply this formula! n(n+1)/2 and n is the no. of terms
a+a*r+a*r^2+...+a*r^n a = first number r = ratio n = "number of terms"-1
It is not possible to answer this question without information on whether the terms are of an arithmetic or geometric (or other) progression, and what the starting term is.
The simplest formula is: t(n) = 2n + 5 for n = 1, 2, 3, ... However, that is not the only formula; there are infinitely many polynomial formulae that can be found that give those five terms first, but for the 6th or further terms vary.
Assuming each term is 3 MORE than the previous term t(n) = -13 + 3*n where n = 1, 2, 3, ...
Permutation Formula A formula for the number of possible permutations of k objects from a set of n. This is usually written nPk . Formula:Example:How many ways can 4 students from a group of 15 be lined up for a photograph? Answer: There are 15P4 possible permutations of 4 students from a group of 15. different lineups
The formula for the sum of the first n terms of an arithmetic progression is Sn = n/2 * (a + l), where Sn is the sum, n is the number of terms, a is the first term, and l is the last term.
You.... have to apply this formula! n(n+1)/2 and n is the no. of terms
RAMANUJANRAMANUJAN
The general electronic configuration of p block elements is ns2 np1-6. This means that the outermost electron shell of p block elements contains electrons in either the np1, np2, np3, np4, np5, or np6 orbitals.
a+a*r+a*r^2+...+a*r^n a = first number r = ratio n = "number of terms"-1
t(1) = 1t(2) = 1t(n) = t(n-2) + t(n-1) for n = 3, 4, 5, ...that is, the first and second terms are 1. After that, each term is the sum of the previous two terms.
The sum of n terms in a harmonic progression is given by the formula ( S_n = \frac{n}{a_1+ \frac{ (n-1)d}{2}} ) where ( S_n ) is the sum of n terms, ( a_1 ) is the first term, d is the common difference.
It is not possible to answer this question without information on whether the terms are of an arithmetic or geometric (or other) progression, and what the starting term is.
The formula to find the sum of a geometric sequence is adding a + ar + ar2 + ar3 + ar4. The sum, to n terms, is given byS(n) = a*(1 - r^n)/(1 - r) or, equivalently, a*(r^n - 1)/(r - 1)
The differences between terms are 7,9,11,15 The differences of these differences are 2,2,2,2 Thus the formula for the sequence begins with n2 The sequence of numbers minus n2 is 5, 9, 13, 17, 21 The difference between the terms is 4 So the formula continues n2+4n The sequence of numbers minus n2+4n is 1, 1, 1, 1, 1 So the formula for the nth term is n2+4n+1
The simplest formula is: t(n) = 2n + 5 for n = 1, 2, 3, ... However, that is not the only formula; there are infinitely many polynomial formulae that can be found that give those five terms first, but for the 6th or further terms vary.