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Q: What is the formula for the nth Term of these sequences 13 21 29 37 45 ...?

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The nth term is 6n+1 and so the next term will be 31

The nth term is: 5-6n

Tn = 1 + 3n

The first differences are 5, 7, 9, 11, 13 and the second differences are 2,2,2,2 so the formula for the nth term is a quadratic. tn = n2 + 2n - 2 (n = 1,2,3,...)

The nth term of a sequence is the general formula for a sequence. The nth term of this particular sequence would be n+3. This is because each step in the sequence is plus 3 higher than the previous step.

13 n 5

The nth term is 3n+7 and so the next number will be 22

The nth term is: 3n+1 and so the next number will be 16

The nth term is 25-4n and so the next term will be 5

As given, the sequence is too short to establish the generating rule. If the second term was 19 and NOT 29, then the nth term is tn = 6*n + 7 or 6(n+1)+1

75988 to the 7th

+9

I suspect that the first term should be "negative 3", ie the sequence is -3, 1, 5, 9, 13, 17, ... The nth term is 4n - 7

The 'n'th term is [ 13 + 5n ].

The 'n'th term is [ 13 + 5n ].

The 'n'th term is [ 13 + 5n ].

The 'n'th term is [ 13 + 5n ].

The 'n'th term is [ 13 + 5n ].

The nth term is 4n - 3

It is: 5n+3 and so the next term is 28

It is: 10n-7 and so the next term is 43

It is 4n+5 and so the next term will be 25

[ 25 - 6n ] is.

14+9n

1+3n