13 n 5
The Nth term formula for oblong numbers is N = N(N+1)
Tn = 1 + 3n
The nth term is: 5-6n
Formula for nth termTn = a + (4n - 1) {where a is the first term and n is natural number}
10n + 1
The Nth term formula for oblong numbers is N = N(N+1)
It is: nth term = 35-9n
Tn = 1 + 3n
The sequence 4, 6, 8, 10 is an arithmetic sequence where each term increases by 2. The nth term formula can be expressed as ( a_n = 4 + (n - 1) \cdot 2 ). Simplifying this gives ( a_n = 2n + 2 ). Thus, the nth term of the sequence is ( 2n + 2 ).
The nth term is: 5-6n
The given sequence is an arithmetic sequence with a common difference of 6. To find the nth term of this sequence, we can use the following formula: nth term = first term + (n - 1) x common difference where n is the position of the term we want to find. In this sequence, the first term is 1 and the common difference is 6. Substituting these values into the formula, we get: nth term = 1 + (n - 1) x 6 nth term = 1 + 6n - 6 nth term = 6n - 5 Therefore, the nth term of the sequence 1, 7, 13, 19 is given by the formula 6n - 5.
Formula for nth termTn = a + (4n - 1) {where a is the first term and n is natural number}
The sequence 1, 3, 6, 10, 15, 21 consists of triangular numbers, where the nth term can be calculated using the formula ( T_n = \frac{n(n + 1)}{2} ). This formula represents the sum of the first n natural numbers. For example, for n = 1, the term is 1; for n = 2, it is 3, and so on. Thus, the nth term is the sum of the integers from 1 to n.
10n + 1
To find the nth term of this sequence, we first need to identify the pattern. The differences between consecutive terms are 5, 9, 13, 17, and so on. These are increasing by 4 each time. This means that the nth term can be calculated using the formula n^2 + 4n + 1. So, the nth term for the sequence 5, 10, 19, 32, 49 is n^2 + 4n + 1.
The given sequence appears to be increasing by 10 each time. To find the nth term, we can use the formula for arithmetic sequences: nth term = first term + (n-1) * common difference. In this case, the first term is 4 and the common difference is 10. Therefore, the nth term for this sequence would be 4 + (n-1) * 10, which simplifies to 10n - 6.
2(n-1)