The Nth term formula for oblong numbers is N = N(N+1)
Tn = 1 + 3n
The nth term is: 5-6n
Formula for nth termTn = a + (4n - 1) {where a is the first term and n is natural number}
15(1)
The Nth term formula for oblong numbers is N = N(N+1)
It is: nth term = 35-9n
Tn = 1 + 3n
The nth term is: 5-6n
The given sequence is an arithmetic sequence with a common difference of 6. To find the nth term of this sequence, we can use the following formula: nth term = first term + (n - 1) x common difference where n is the position of the term we want to find. In this sequence, the first term is 1 and the common difference is 6. Substituting these values into the formula, we get: nth term = 1 + (n - 1) x 6 nth term = 1 + 6n - 6 nth term = 6n - 5 Therefore, the nth term of the sequence 1, 7, 13, 19 is given by the formula 6n - 5.
Formula for nth termTn = a + (4n - 1) {where a is the first term and n is natural number}
To find the nth term of this sequence, we first need to identify the pattern. The differences between consecutive terms are 5, 9, 13, 17, and so on. These are increasing by 4 each time. This means that the nth term can be calculated using the formula n^2 + 4n + 1. So, the nth term for the sequence 5, 10, 19, 32, 49 is n^2 + 4n + 1.
2(n-1)
(n^2+n)/2
15(1)
The nth term is: 3n+1 and so the next number will be 16
This is an arithmetic sequence which starts at 14, a = 14, and with a common difference of -1, d = -1. We can use the nth term formula an = a + (n - 1)d to get an = 14 + (n - 1)(-1) = 14 - n + 1 = 15 - n.