It is: nth term = 35-9n
The nth term is 5n-3 and so the next term will be 22
The nth term is 25-4n and so the next term will be 5
The nth term in the arithmetic progression 10, 17, 25, 31, 38... will be equal to 7n + 3.
7n - 4
I suspect that the first term should be "negative 3", ie the sequence is -3, 1, 5, 9, 13, 17, ... The nth term is 4n - 7
The nth term is: 3n+2 and so the next number will be 20
Just subtract 9.
The nth term is 7n-4 and so the next number in the sequence is 31
7(n2-1) - 4
It is: 27-2n
5, 11, 17, 23, 29
The nth term is 2n+5 and so the next number is 17
9, 17, 25, 33, 41
5, 8, 11, 14 and 17.
You can see that all the numbers go up by 7. This means that the first part of the nth term rule for this sequence is 7n. Now, you have to find out how to get from 7 to 3, 14 to 10, 21 to 17 ... this is because we are going up in the 7 times table. To get from the seventh times table to the sequence, you take away four. So the answer is : 7n-4
That depends what the pattern of the sequence is.
This is an Arithmetic Series/Sequence. In general the nth term, A(n) = a + (n - 1)d....where a is the 1st term and d is the common difference. In this question, the 1st term equals 1 and the common difference is 4. Then the nth term, A(n) = 1 + (n - 1) x 4 = 1 + 4n - 4 = 4n - 3.
It seems that the term increases 5 at a time, so (if this tendency continues) it's quite clear that the sequence is of the form 5n+k, for some constant "k". With a little experimentation, you can find that "k" should be 2.
The nth term is 3n+2 and so the next number will be 17
The sequence goes up by 5 each time; the first term is two. So the nth term is 2 + 5n. n=50 => 2+50*5 = 252.