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Using information from the Wolframalpha site. It seems that this integral can't be expressed as a finite amount of standard functions; you can go to the Wolfram Alpha site, and type "integral x^x", to get a series expansion if you are interested.

Q: What is the integral of x raised to power x?

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If x has the power 2 then you want the integral of x2, I think. When you integrate this you get : x3/3 , plus a constant.

x raised to the power 36 is x36. Without a value for x, there is nothing to solve!

replace square root o x with t.

x to the power of 1 means x

Related questions

The integral of 3x is ln(3)*3x. Take the natural log of the base and multiply it by the base raised to the power.

integral (a^x) dx = (a^x) / ln(a)

This integral cannot be performed analytically. Ony when the integral is taken from 0 to infinity can it be computed by squaring the integral and applying a change of variable (switching to polar coordinates). if desired I could show how to do this.

integral of e to the power -x is -e to the power -x

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(e^x)^8 can be written as e^(8*x), so the integral of e^(8*x) = (e^(8*x))/8 or e8x/ 8, then of course you have to add a constant, C.

If x has the power 2 then you want the integral of x2, I think. When you integrate this you get : x3/3 , plus a constant.

You add one to the power, and then divide by the power that it has so you would have: Integral of x = (x^2)/2 Integral of x^2 = (x^3)/3 Etc.

The antiderivative, or indefinite integral, of ex, is ex + C.

The integral would be 10e(1/10)x+c

x raised to the power 36 is x36. Without a value for x, there is nothing to solve!

replace square root o x with t.