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It's 540 degrees for any pentagon,

regular or not.

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Q: What is the interior angle sum of regular pentagon?

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The sum of the interior angles of a pentagon = (5-2)*180 = 540 degrees. IF the pentagon is regular, then each of its interior angle is the same. In that case, each will be 540/5 = 108 degrees.

The sum of interior and exterior angle = 180. The interior angle of a regular pentagon = (n-2)x180 / n = (5-2)x180/5 = 108 The exterior angle = 180 - 108 = 72 The interior angle is 35 degrees greater than exterior angle.

The sum of the interior angles of a polygon with n sides is (n-2)*180 degrees. So, for a pentagon, n= 5. The sum of the interior angles is (5-2)*180 = 3*180 = 540 degrees.

540o

Mathematically - A regular pentagon has interior angles and sides equal. Bisecting each interior angle and extending a line segment to the center gives you five equal angles (360o/5=72o). Using the triangle formed by two line segements and a side of the pentagon we know the sum of interior angles of each triangle equals (180o) and we know one angle is 72o. The sum the other two interior angles of each triangle equals (180o-72o=108o) which equals each interior angle of the pentagon (equal to the sum of these two angles). Thus the exterior angle of each corner of the pentagon equals (360o-108o=252o). :-)

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The sum of the five interior angles of ANY pentagon is 540 degrees.If the pentagon is regular, then each angle is 108 degrees.

The sum of the interior angles of a pentagon = (5-2)*180 = 540 degrees. IF the pentagon is regular, then each of its interior angle is the same. In that case, each will be 540/5 = 108 degrees.

For a regular polygon with sides n, the sum of the interior angles = (n-2)180Therefore, a regular polygon has interior angle sum equal to 540o.(5-2)180=(3)180=540

To the nearest tenth, the interior angle of a regular pentagon is 108.0o In a regular pentagon, the sum of the interior angles is (5 - 2) x 1800 = 3 x 1800 = 540o In a regular pentagon, the interior angles are all the same size and are 5400 ÷ 5 = 108o which to the nearest tenth is 108.0o

Pentagon = 5 sides.For regular pentagon: 360/5 = 72180 - 72 = 108 degrees at each interior angle.For non-regular pentagons, each interior angle may differ but the sum of the interior angles will be the same as a regular pentagon = 5 x 108 = 540 degrees.

The measurement of an interior angle of a pentagon depends on whether the pentagon is a "regular pentagon". The sum of the measures of the interior angles of any polygon can be calculated using the formula (n-2)180, where n = the number of sides. If the pentagon is a regular pentagon, then all of the interior angles are congruent (i.e. : 144 degrees). Interior angle is the inside angle of any angular object. A triangle for instance has three outside angles and three interior angles, the angles of the points from the inside.

The sum of interior and exterior angle = 180. The interior angle of a regular pentagon = (n-2)x180 / n = (5-2)x180/5 = 108 The exterior angle = 180 - 108 = 72 The interior angle is 35 degrees greater than exterior angle.

If the pentagon is regular all you need do is divide 540 by 5. If it isn't regular, we can't help.

The sum of the interior angles in a pentagon is (5-2)180 degrees or 3x180 degrees=540. Since it is regular each angle has the same measure and so each is 540/5=108 degrees.

A pentagon

The sum of the interior angles of a polygon with n sides is (n-2)*180 degrees. So, for a pentagon, n= 5. The sum of the interior angles is (5-2)*180 = 3*180 = 540 degrees.

The sum of the interior angles add up to 540 degrees. The sum of the exterior angles add up to 360 degrees.