1800 square cm.
Yes providing that it is an equilateral triangle or a a right angle isosceles triangle other wise it's not possible
I do believe you mean RIGHT triangle when you said perpendicular triangle. A right triangle has two legs and a hypotenuse. The area of a right triangle is 1/2 * (first leg) * (second leg) How do you determine which ones are the legs and which one is the hypotenuse? The hypotenuse is ALWAYS the largest number. So, choose the 2 smallest numbers.
Area of a right angle triangle is: 0.5*base*height
1/2*base of triangle*height(the perpendicular)=Area of right angled triangle
You mean the largest possible area with a perimeter of 18, right? Well, the largest area is with a circle, which has area 81/pi which is approximately 25.7831 If you need a rectangular area, the largest is a square of width=length (definition of square) = 4.5 This has area 4.52 which is 20.25, substantially less than the circles area...
There is no right triangle on the right! (Ignore the length of the hypotenuse of a right triangle.) if you have the length of the two legs (base and the upright side): (base x upright) ÷ 2 = area of the right angle triangle.
Yes. The two equal sides would measure 3.
A right triangle is easy, simply multiply the two sides and divide by two. A non-right triangle is a bit more of a challenge. You have to make it a right triangle by adding a right triangle to it. Calculate and then subtract the area of what you had to add.
The area of a 12cm by 5cm right-angled triangle is: 42 cm2
how to find the perimeter of a right angled triangle using the area
The area of a right-angle triangle is half of the area of a rectangle 8cm x 4cm. Find the rectangle area and divide by half to find the area of the right-angle triangle. Therefore: 8 x 4 / 2 = 16cm2 * * * * * The above answer assumes that the two given lengths are the shorter legs of the triangle. It is, however, possible that these are the hypotenuse and one leg. In that case, the second leg is 4*sqrt(2) cm and the area of the triangle is 4 * 4*sqrt(2) / 2 = 8*sqrt(2) = 11.31 cm2.
The area of any triangle is1/2 of (the length of the triangle's base) times (the triangle's height).