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There is no last digit in the square root of 2. It is an irrational number - and continues forever.
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How do you find the squareroot of a number?
Ignore the last two digits of the number called out by the spectator and choose the memorised square which is just lower (or equal) to the remaining number. The corresponding square root is the first digit. of your answer Now consider the last digit of the number called out by the spectator. If this is 0 or 5, then you immediately know that the last digit of your answer is also 0 or 5. In all other cases, the last digit of the number called out will indicate two possible values for the last digit of the square root. For example, if the last digit is 9, then the square root may end in either 3 or 7.
Find the 3 digit no whose last digit is the square root of the first digit and second digit is the sum of the other two digits?
Ans: 462
Two -digit number whose cube root is the square root of the sum of its digit?
27
How do you find the square root and cube root of 4096?
4096 is 212 The square root will be 26 The cube root will be 24 How to find the square root of 4096? It will be a two digit number. Look at the last digit 6. This can be obtained only if the last digit of the root is 6 or 4. Since the first two digit part of the given number is 40, it suggests that the first digit of the root is 6 (if you think it can be 5, 25 is too far from 40). So is the squaree root 66 or 64? Since 36 is closer to 40, then the root can be 64. Check: 64; 6242 = 3616 + 2(6*4)*10 = 3616 + 480 = 4096 Thus, 642 = (26)2 = 212
What single digit number is both the square root and divisible of another single digit number?
There are two solutions to the question:- 2 & 3 2 is the square root of 4 - and a factor of 4 (and 8) 3 is the square root of 9 - and is also a factor of 9
A square whose last two digits are its square root?
252 = 625
What two digit number whose cube root is the square root of the sum of its digit?
Well, let's see. Perfect cubes that are two digits: 27 64 Could it be 27? Well, 2+7 is 9, and that's a perfect square with a square root of 3, and the cube root of 27 is three. Looks like we've found our answer, especially since 6+4 = 10, which is NOT a perfect square.
The sum of the digits of a certain two-digit number equals the square root of the number What is the number?
81
What is a two digit number whose sum of those digits is the square root of that number?
The number is 81.
The two-digit number whose cube root is the square root of the sum of its digits?
27 27 = 3*3*3 (3 cubed = 27) 2+7 = 9 The square root of 9 is 3.
Square root of 2 Times Square root of 2?
The square root of two times the square root of two equals two
How do you find a square root to the nearest tenth?
-- Calculate the square root in the usual fashion, continuing until you have two digits after the decimal point. -- If the second digit after the point is 4 or less, discard it, and what's left is your answer. -- If the second digit after the point is 5 or more, discard it, and increase the first digit after the point by '1' to get your answer.
