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What else can I help you with?
What is the last digit of the number 2 to the 45 power?
2 (The answer is 35184372088832)
What is last unit in 2 to the power of 1997?
The last digit of a number raised to a power can be determined by finding a pattern in the units digits of the number's powers. For 2 raised to the power of 1997, the units digit will follow a pattern of 2, 4, 8, 6. Since 1997 is one less than a multiple of 4, the last digit will be 8.
What is the last digit of the number 42012?
The last digit of the number 42012 is 2.
How do you add a 3 digit number and a 2 digit number?
Nothing special about it. 489 +65 554
When you subtract 2 from 7 the estimate is five?
Yes. 7 - 2 is 5, and if the last digit on one number is 7 and the last digit on one you are subtracting from it is 2, the last digit on the answer will be a 5. That will help you in doing estimations.
What is a number that has 2 digits 13 as a factor and the sum of the digit is 11?
65
What The rule of a number divide by 8?
If you mean what is the divisibility rule for the number 8: There are two: 1. For any power n of 2 the last n digits of the number must be divisible by 2 to the power n. 8 = 2³ → If the last 3 digits are divisible by 3, then so is the whole number. 2. Add the last (ones) digit to 2 times the tens digit to 4 times the hundreds digit; if this sum is divisible by 8, then so is the original number. As the test can be repeated on the sum, repeat until a single digit remains. If, and only if, this digit is 8 will the number be divisible by 8.
What is the unit’s digit in the expansion of 2 raised to 725?
The unit's digit in the expansion of 2 raised to the 725th power is 8. This can be determined by using the concept of the "unit's digit law". This law states that the units digit of a number raised to any power is the same as the units digit of the number itself. In this case, the number is 2, which has a units digit of 2, so the units digit of 2 to the 725th power is also 2. However, this is not the final answer. To get the unit's digit of 2 to the 725th power, we must use the "repeating pattern law". This law states that when a number is raised to any power, the unit's digit will follow a repeating pattern. For 2, this pattern is 8, 4, 2, 6. This means that the units digit of 2 to any power will follow this pattern, repeating every 4 powers. So, if we look at the 725th power of 2, we can see that it is in the 4th cycle of this repeating pattern. This means that the units digit of 2 to the 725th power is 8.
How does the divisibility rule for 4 and 8 work?
A number is a multiple of 4 if the last 2 digits are a multiple of 4 The 10s digit is even and the last digit is 0, 4 or 8 The 10s digit is odd and the last digit is 2 or 6 A number is a multiple of 8 if the last 3 digits are a multiple of 8 The 100s digit is even and the last 2 digits are a multiple of 8 The 100s digit is odd and the last 2 digits are 4 times an odd number
What is the last number in 8 to the power of 2015?
I assume you mean the last digit. The idea is to find a pattern: 8 to the power 1 ends with 8 8 to the power 2 ends with 4 8 to the power 3 ends with 2 (to figure this out, I just multiplied 4 x 8) 8 to the power 4 ends with 6 (once again, multiply the last digit of the previous power x 8) 8 to the power 5 ends with 8 8 to the power 6 ends with 4 ... As you can see, it all repeats, with a period of 4. Therefore, any exponent that is a multiple of 4 will end with 6. Find the nearest multiple of 4 that is smaller than 2015, then continue calculating - always with the last digit.
Round 7.37 to 1 decimal place?
If the last digit in 7.37 is less than 5, then remove the last digit. One Decimal Place Rule #2: If the last digit in 7.37 is 5 or more and the second to the last digit in 7.37 is less than 9, then remove the last digit and add 1 to the second to the last digit.
How many positive four digit integers have 1 as their first digit and 2 or 5 as their last digit?
There are 200 positive four digit integers that have 1 as their first digit and 2 or 5 as their last digit. There are 9000 positive four digit numbers, 1000 through 9999. 1000 of them have 1 as the first digit, 1000 through 1999. 200 of them have 2 or 5 as their last digit, 1002, 1005, 1012, 1015, ... 1992, and 1995.
