The greatest common multiple of any set of integers is infinite.
The greatest factors of A, B, and C, respectively, are the absolute values of A, B, and C. The greatest common factor of A, B, and C is 1.
LCM(8, C, A) = 8*C*A.
The following code for example is a solution (you could do it with less variables, but this is more readable):int GCD(int a, int b){int n, k, c;n = (a>b)?a:b;k = (a>b)?b:a;while (k){c = n%k;n=k;k=c;}return n;}
b 108
If the greatest common factor/divisor of A and B is 1 then they are coprime - they do not share any prime factors. Multiplying both through by C means, obviously, that each number now divides by C. In fact, C is their greatest common divisor, since AC and BC do not have further common factors after C is taken out. Hence the GCF of AC and BC is not merely a factor of C - it is C. (The question makes sense only if A, B and C are integers.)
A + B is also a multiple of C. ------------------------------------------- let k, m and n be integers. Then: A = nC as A is a multiple of C B = mC as B is a multiple of C → A + B = nC + mC = (n + m)C = kC where k = n + m kC is a multiple of C. Thus A + B is a multiple of C.
It is b: 80
If A and B are multiples of C, then A + B is also a multiple of C: If A is a multiple of C then A = mC for some integer m If B is a multiple of C, then B = nC for some integer n → A + B = mC + nC = (m + n)C = kC where k = m + n and is an integer → A + B is a multiple of C
C is this your homework??
Alright, buckle up, buttercup. To find the least common multiple of 10ab and 14abc, you need to break down both numbers into their prime factors. The prime factors of 10ab are 2 * 5 * a * b, while the prime factors of 14abc are 2 * 7 * a * b * c. Now, the least common multiple will be the product of all the unique prime factors with the highest power they appear in either number. So, the least common multiple of 10ab and 14abc is 2 * 5 * 7 * a * b * c. Hope that clears things up for ya!
a). The least common multiple of 4 and 6 is 12 . b). The least common multiple of 3 and 8 is 24 . c). The least common multiple of 2 and 12 is 12 . d). The least common multiple of 3 and 6 is 6 . Gosh, I guess they all have.
There are none because there is no such thing as a Greatest Common Multiple (GCM). If {a, b, c, ... x} is any set of integers, then a*b*c*...*x is a common multiple. Then twice that number is also a common multiple and is greater. And then, twice THAT number is a common multiple and greater still. It is easy to show that this process can go on for ever and so there is no such thing as a GCM.
To answer that, you'll need to have a numerical value for the letters.
To calculate the least common multiple (lcm) of decimals (integers) and fractions you first need to calculate the greatest common divisor (gcd) of two integers: int gcd (int a, int b) { int c; while (a != 0) { c = a; a = b % a; b = c; } return b; } With this function in place, we can calculate the lcm of two integers: int lcm (int a, int b) { return a / gcd (a, b) * b; } And with this function in place we can calculate the lcm of two fractions (a/b and c/d): int lcm_fraction (int a, int b, int c, int d) { return lcm (a, c) / gcd (b, d); }
its the 3rd highest felony you can get think for a second A B C, A is the highest.
We need the numbers more than we need the choices.
Boron (B) has the highest ionization energy among the elements listed.