8 length 8 width
Perimeter = 2*(7+9) = 32 units.
Perimeter = 2*(L + W)= 2*(45 + 32) = 2*77 = 154 cm.
32 cm
w= widthw+4=length2(w+l)= perimeter2(w+w+4)=32 substitution2(2w+4)=324w+8=32 distributive property4w=32-8 subtraction property of equality4w=24w=6 division property of equalitylength is 6+4 or 10cm.
6
32 cm
Length + width = half of perimeter ie 36.7 in. If length is 4.7 in then width is 32 in.
7 feet
I think you mean the width is 6. The answer depends entirely on what the length of the rectangle is. For example, if it is a square, so that the length and width are both 6, the answer is 24. I the length is 10, the perimeter is 32. In general, just add the width (6) to the length and double the sum to get the perimeter.
Perimeter = 2*(7+9) = 32 units.
Perimeter = 32 inches. Area = 55 square inches.
They will be both the same because the perimeter of the square is 32 units and the perimeter of the rectangle is also 32 units
Perimeter = 2*(L + W)= 2*(45 + 32) = 2*77 = 154 cm.
twelve -------------------- The original rectangle is 12 feet in length and 5 feet in width. The length (12) is 7 feet greater than the width (5 feet). Were the length decreased by 3 (12 - 3 = 9) and the width increased by 2 (5 + 2 = 7), the perimeter would be 32 feet (9 + 7 + 9 + 7 = 32).
It is: 2(32+56) = 176 feet
32 meters The perimeter (distance around the outside) = length + width + length + width P = 2L + 2W 2 (9) + 2 (7) = 18 + 14 = 32 also: P = 2 (L + W) 2(9 + 7) = 32
32