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Q: What is the length and width of a rectangle with a perimeter of 10cm?

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Perimeter = 2 lengths and 2 widths In your case length + width = 25cm If length is 5cm more than width then length = 15cm and width = 10cm

Width = 10cm.. i think Length = 68cm

I assume you are referring to a rectangle. Just add the lengths of all four sides.

length=18cm width=10cm (you use a system of equations: 2L+2W=56, L=2W-2)

40cm2

infinitely far

In order to find the area of a rectangle, multiply the length by the width of the rectangle. For example: If the length of a rectangle is 5cm and the width of a rectangle is 2cm, then the area of the rectangle would be 5cm X 2cm = 10cm².

what is the perimeter of a 11cm x 10cm rectangle answer 42

First find the dimensions of the rectangle. Let its length be 2x and its width be x: 2(2x+x) = 60 4x+2x = 60 6x = 60 x = 10 Therefore: length = 20cm and the width = 10cm Area = length*width Area = 200cm2

The perimeter of a rectangle is equal to 2 x length + 2 x width. (2 x 24 cm) + (2 x 10 cm) = 48 cm + 20 cm = 68 cm

The diagonal is 26cm

what is the perimeter of a rectangle that's 10cm x 7cm

area = length x width area = 12 x 10 = 120 square cm

10cm is a length. You can only find perimeter (length all the way round) if there is a shape!

What is a rectangle were the area is 10 and the perimeter

30cm

28cm

The volume of a solid rectangle is equal to Length x Width x Height. So, 20cm x 10cm x 5cm would be 1000cm cubed.

10 × 5 = 50Therefore, the width is 5 centimetres.

p=2l+2w 34= 2(10) +2w 34= 20 +2w 14= 2w w=7

w= widthw+4=length2(w+l)= perimeter2(w+w+4)=32 substitution2(2w+4)=324w+8=32 distributive property4w=32-8 subtraction property of equality4w=24w=6 division property of equalitylength is 6+4 or 10cm.

k

The greatest area is when the rectangle is a square. A perimeter of 10cm equates to each side of square measuring 2.5cm and then the area = 2.52 = 6.25 sq cm. The least area occurs when the rectangle is shaped like a long, narrow slit. So that the length is as close to 5cm as possible and the width is as narrow as possible. Let's say that the length is 4.9 cm and the width 0.1 cm, then the area = 4.9 x 0.1 = 0.49 sq cm. If these dimensions are changed slightly to length 4.95 and width 0.05 then the area = 4.95 x 0.05 = 0.2475 sq cm. As the length gets closer to 5 then the width gets closer to 0 and the area becomes almost 0 sq cm.

1 x 4 or 2 x 3

we know that , area of rect = l * b= 10 *5.5 = 55 cm^2