The length is 3cm and the width is 2cm. (Or the other way around).
Also a 1 cm x 4 cm rectangle and a 0.5 cm x 4.5 cm would do it too, since they are rectangles whose 4 sides add up to 10 cm.
First find the dimensions of the rectangle. Let its length be 2x and its width be x: 2(2x+x) = 60 4x+2x = 60 6x = 60 x = 10 Therefore: length = 20cm and the width = 10cm Area = length*width Area = 200cm2
The perimeter of a rectangle is equal to 2 x length + 2 x width. (2 x 24 cm) + (2 x 10 cm) = 48 cm + 20 cm = 68 cm
28cm
The volume of a solid rectangle is equal to Length x Width x Height. So, 20cm x 10cm x 5cm would be 1000cm cubed.
w= widthw+4=length2(w+l)= perimeter2(w+w+4)=32 substitution2(2w+4)=324w+8=32 distributive property4w=32-8 subtraction property of equality4w=24w=6 division property of equalitylength is 6+4 or 10cm.
Width = 10cm.. i think Length = 68cm
Perimeter = 2 lengths and 2 widths In your case length + width = 25cm If length is 5cm more than width then length = 15cm and width = 10cm
I assume you are referring to a rectangle. Just add the lengths of all four sides.
length=18cm width=10cm (you use a system of equations: 2L+2W=56, L=2W-2)
40cm2
First find the dimensions of the rectangle. Let its length be 2x and its width be x: 2(2x+x) = 60 4x+2x = 60 6x = 60 x = 10 Therefore: length = 20cm and the width = 10cm Area = length*width Area = 200cm2
The diagonal is 26cm
what is the perimeter of a 11cm x 10cm rectangle answer 42
p=2l+2w 34= 2(10) +2w 34= 20 +2w 14= 2w w=7
infinitely far
The perimeter of a rectangle is equal to 2 x length + 2 x width. (2 x 24 cm) + (2 x 10 cm) = 48 cm + 20 cm = 68 cm
In order to find the area of a rectangle, multiply the length by the width of the rectangle. For example: If the length of a rectangle is 5cm and the width of a rectangle is 2cm, then the area of the rectangle would be 5cm X 2cm = 10cm².