The length is 3cm and the width is 2cm. (Or the other way around).
Also a 1 cm x 4 cm rectangle and a 0.5 cm x 4.5 cm would do it too, since they are rectangles whose 4 sides add up to 10 cm.
First find the dimensions of the rectangle. Let its length be 2x and its width be x: 2(2x+x) = 60 4x+2x = 60 6x = 60 x = 10 Therefore: length = 20cm and the width = 10cm Area = length*width Area = 200cm2
The perimeter of a rectangle is equal to 2 x length + 2 x width. (2 x 24 cm) + (2 x 10 cm) = 48 cm + 20 cm = 68 cm
28cm
The volume of a solid rectangle is equal to Length x Width x Height. So, 20cm x 10cm x 5cm would be 1000cm cubed.
w= widthw+4=length2(w+l)= perimeter2(w+w+4)=32 substitution2(2w+4)=324w+8=32 distributive property4w=32-8 subtraction property of equality4w=24w=6 division property of equalitylength is 6+4 or 10cm.
The perimeter of a rectangle is calculated by adding together the lengths of all its sides. In this case, the rectangle has two sides of length 10cm and two sides of length 3cm. Therefore, the perimeter is calculated as 10cm + 10cm + 3cm + 3cm = 26cm.
Width = 10cm.. i think Length = 68cm
Perimeter = 2 lengths and 2 widths In your case length + width = 25cm If length is 5cm more than width then length = 15cm and width = 10cm
length=18cm width=10cm (you use a system of equations: 2L+2W=56, L=2W-2)
40cm2
First find the dimensions of the rectangle. Let its length be 2x and its width be x: 2(2x+x) = 60 4x+2x = 60 6x = 60 x = 10 Therefore: length = 20cm and the width = 10cm Area = length*width Area = 200cm2
The diagonal is 26cm
what is the perimeter of a 11cm x 10cm rectangle answer 42
infinitely far
p=2l+2w 34= 2(10) +2w 34= 20 +2w 14= 2w w=7
The perimeter of a rectangle is equal to 2 x length + 2 x width. (2 x 24 cm) + (2 x 10 cm) = 48 cm + 20 cm = 68 cm
In order to find the area of a rectangle, multiply the length by the width of the rectangle. For example: If the length of a rectangle is 5cm and the width of a rectangle is 2cm, then the area of the rectangle would be 5cm X 2cm = 10cm².