The length is the square root of two, about 1.414 inches.
By the Pythagoras theorem, the diagonal of the square is the hypotenuse of the angle formed by any two connected sides. And sq rt (12 + 12) = sq rt 2
A square with 2-inch sides has a diagonal of: 2.828 inches.
A square with a 30-inch diagonal measurement has sides of 21.21 inches in length.
The diagonal of a 20 inch square is the square root of 800 inches, approximately 28.284 inches, which is the sum of the squares of two sides.
Side = sqrt(72) inches = 8.49 in approx.
Approximately 35.35 inches
A square with 2-inch sides has a diagonal of: 2.828 inches.
A square with a 30-inch diagonal measurement has sides of 21.21 inches in length.
The diagonal of a 20 inch square is the square root of 800 inches, approximately 28.284 inches, which is the sum of the squares of two sides.
Use Pythagoras' theorem to find the length of the diagonal in the square
sqrt (2 x 36 x 36) ie 50.94 inches
diagonal is 13 inch length of the rectangle of 12 and 5 inches sides
If the diagonal is 10 we know all sides are equal so from pythagoraen theorem each side is 7.07 inch length Area = 7.07 x 7.07 = 50
The diagonal of a 101 inch square is about 142.84 inches.
Side = sqrt(72) inches = 8.49 in approx.
The diagonal is 517.602 inches.
The diagonal of an 18 inch square is about 25.46 inches. (18 times the square root of 2).
You use the Pythagorean Theorem, which says that the square of the hypotenuse of a right triangle is the sum of the squares of the other two sides. Two adjacent sides of a square (or any rectangle) together with a diagonal form a right triangle. In the case of a square, the triangle is isosceles. Calling the length of a side of the square (17 inches) one unit, the theorem tells us that the hypotenuse is the square root of 2 units. Therefore the diagonal of the square is 17 times the square root of 2 inches, which is about 24 inches.