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How do you find area of square if diagonal is given?
Using Pythagoras' theorem which says that the square on the hypotenuse (in this case the diagonal) is equal to the sum of the squares on the other two sides (which in the case of a square would be equal in length). so if the diagonal measured 10 units, the square on the diagonal would be 100 square units. And as this = 2*the squares on the other sides, the square on one side would be 100/2 = 50 square units. As a square has sides of equal length the square on one side is actually the area of the square. i.e. the area of a square with a diagonal of 10 units is 50 square units. or generically the area of a square with a diagonal of length 'x' = (x2)/2
The width of a rectangle is 10 meters and its area is 120 square meters What is the length of the diagonal?
The diagonal is 15.620 meters.
What is the area of a square with a circle of a radius of 5 inches?
If the circle is inscribed in the square, the side length of the square is the same as the diameter of the circle which is twice its radius: → area_square = (2 × 5 in)² = 10² sq in = 100 sq in If the circle circumscribes the square, the diagonal of the square is the same as the diameter of the circle; Using Pythagoras the length of the side of the square can be calculated: → diagonal = 2 × 5 in = 10 in → side² + side² = diagonal² → 2 × side² = diagonal² → side² = diagonal² / 2 → side = diagonal / √2 → side = 10 in / √2 → area _square = (10 in / √2)² = 100 sq in / 2 = 50 sq in.
If the area of a square is 72 sq in find the radius?
The radius of a square is the radius of the circumcircle, ie the distance from the centre of the square to any vertex, which is half the length of the diagonal of the square. Using Pythagoras: diagonal^2 = side^2 + side^2 → diagonal = √(2 x side^2) area = side^2 → diagonal = √(2 x area) radius = 1/2 x diagonal = 1/2 x √(2 x area) → radius = 1/2 x √(2 x 72 sq in) = 1/2 x √(144 sq in) = 1/2 x 12 in = 6 in.
What is the diagonal of a 5 feet by 10 feet area?
Assuming you are talking about a rectangular area, the diagonal would be found using the Pythagorean Theorem. 5^2 + 10^2 = d^2, so 125 = d^2, then take square root of both sides. This means the diagonal is approximately 11.18 feet. It is exactly 5√5 feet.
What is the area of a square if the diagonal is 10 inches?
The area of square is : 100.0
The area of a square garden is 50m how long is the diagonal?
The garden's diagonal is 10 meters.
How do you find area of square if diagonal is given?
Using Pythagoras' theorem which says that the square on the hypotenuse (in this case the diagonal) is equal to the sum of the squares on the other two sides (which in the case of a square would be equal in length). so if the diagonal measured 10 units, the square on the diagonal would be 100 square units. And as this = 2*the squares on the other sides, the square on one side would be 100/2 = 50 square units. As a square has sides of equal length the square on one side is actually the area of the square. i.e. the area of a square with a diagonal of 10 units is 50 square units. or generically the area of a square with a diagonal of length 'x' = (x2)/2
What is the area of a square with a diagonal of 10 cm?
Area = 50 cm2
The area of a square is 100 The length of its diagonal is approximately?
If the area of a square is 100, then its side length is 10. If we draw in a diagonal, then we know by the Pythagorean formula that the diagonal's length is sqrt(10^2 + 10^2) = sqrt(200) = 10*sqrt(2).The square root of 2 is approximately 1.414, so the diagonal's length is approximately 10*1.414 =14.14* The diagonal of any square is the side length times (sq rt 2).
The width of a rectangle is 10 meters and its area is 120 square meters What is the length of the diagonal?
The diagonal is 15.620 meters.
What is area of square whose diagonal is 10?
If diagonal is 10 then each side is sqrt 50 (Pythagoras) and area is sqrt 50 x sqrt 50 ie 50
The area of a square garden is 50 m and sup2. How long is the diagonal?
It is 10 metres.
What is the length of the diagonal of a 10 by 10 ft square?
To find the length of the diagonal of a square, we can use the Pythagorean theorem. In a square, the diagonal divides the square into two right-angled triangles. The Pythagorean theorem states that the square of the length of the diagonal is equal to the sum of the squares of the two sides. Therefore, for a 10 by 10 ft square, the length of the diagonal would be the square root of (10^2 + 10^2) which is √(100 + 100) = √200 = 10√2 feet.
What is the area of a square with a circle of a radius of 5 inches?
If the circle is inscribed in the square, the side length of the square is the same as the diameter of the circle which is twice its radius: → area_square = (2 × 5 in)² = 10² sq in = 100 sq in If the circle circumscribes the square, the diagonal of the square is the same as the diameter of the circle; Using Pythagoras the length of the side of the square can be calculated: → diagonal = 2 × 5 in = 10 in → side² + side² = diagonal² → 2 × side² = diagonal² → side² = diagonal² / 2 → side = diagonal / √2 → side = 10 in / √2 → area _square = (10 in / √2)² = 100 sq in / 2 = 50 sq in.
What is the diagonal of a square with a side of 10?
14 The ratio of the side of a square to the diagonal is 1.4.
If the area of a square is 72 sq in find the radius?
The radius of a square is the radius of the circumcircle, ie the distance from the centre of the square to any vertex, which is half the length of the diagonal of the square. Using Pythagoras: diagonal^2 = side^2 + side^2 → diagonal = √(2 x side^2) area = side^2 → diagonal = √(2 x area) radius = 1/2 x diagonal = 1/2 x √(2 x area) → radius = 1/2 x √(2 x 72 sq in) = 1/2 x √(144 sq in) = 1/2 x 12 in = 6 in.
