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What is the diagonal of 11 square inches?
As no shape has been given for the area it is impossible to given the length of the diagonal - the diagonal can be ANY length greater than 0 (assuming you can define what diagonal means for the shape). If you are referring to a square with an area of 11 square inches then: Using Pythagoras: diagonal² = side² + side² = 2 × side² → side² = diagonal² ÷ 2 area = side² = diagonal² ÷ 2 → diagonal² = 2 × area → diagonal = √(2 × area) = √(2 × 11 sq in) = √22 in ≈ 4.69 in If you mean an 11 inch square, ie a square with 11 inches along each side: Use Pythagoras: Diagonal² = √(2 × sidelength²) → diagonal = side_length × √2 → diagonal = 11 in × √2 ≈ 15.6 in
What is the diagonal of an 15 inch square?
About 21.2 inches.
What is the area of a 1 inch square?
The area of a square is calculated by multiplying the length of one side by itself. In this case, if the square has a side length of 1 inch, you would multiply 1 inch by 1 inch, which equals 1 square inch. Therefore, the area of a 1 inch square is 1 square inch.
What is the volume of the rectangular box with a height of 5 length of 7 and a diagonal of 6?
Volume is a physical variable, thus in order to evaluate the volume it is needed to give measurements units to the sides dimensions. For example, if length is in inch, height in meters and diagonal in cm, you have to convert all in the same measurement unit before proceeding. Let us assume that all the measures are in meters. In this case, we can apply the fact that the square diagonal (d) is the sum of the squares of all the sides (x, y and z). Thus d2 = x2 + y2 + z2 From this equation we see that, if the numbers are all in the same unit of measure, the diagonal cannot be smaller than one side, thus it does not exist a rectangular box with a side equal to 7 m and a diagonal equal to 6 m.
A cube with 2 inch sides is placed on a cube with 3 inch sides then a cube with 1 inch sides is placed on the 2 inch cube what is the surface area of the 3 cube tower?
To find the total surface area of the 3-cube tower, we need to calculate the surface area of each cube individually and then add them together. The surface area of a cube is given by 6 times the side length squared. For the 3-inch cube: 6 * 3^2 = 54 square inches For the 2-inch cube: 6 * 2^2 = 24 square inches For the 1-inch cube: 6 * 1^2 = 6 square inches Adding these together: 54 + 24 + 6 = 84 square inches Therefore, the total surface area of the 3-cube tower is 84 square inches.
