Points: (-5, 4) and (3, -6)
Length: (-5-3)2+(4--6)2 = 164 and the square root of this is the diameter
In general, a "chord", but the particular set of chords that pass through the center are called diameter.
Infinitely many. Each point on the circumference of a semicircle can be one end of a diameter and there are infinitely many points in a line segment of any length.
End points: (10, -4) and (2, 2) Midpoint: (6, -1) which is the centre of the circle Distance from (6, -1) to any of its end points = 5 which is the radius Therefore the Cartesian equation is: (x-6)^2 +(y+1)^2 = 25
End points of diameter: (5, 7) and (9, 3) Midpoint of diameter which is the centre of circle: (7, 5)
diameter
Diameter end points: (2, -3) and (8, 7) Centre of circle: (5, 2) Length of diameter: 2 times square root of 34 Equation: (x-5)^2+(y-2)^2 = 34 which in effect is the radius squared Area in square units: 34*pi
In general, a "chord", but the particular set of chords that pass through the center are called diameter.
how to find end points of a diameter for (3,-4) and (7,2)
In geometry a diameter of a circle is defined as a straight line which passes through the centre of a circle and whose end points both lie on the circle.The length of this line can be used to find both the area and circumference of a circle.C = pi(d) A = pi(d)2/4Where:c = circumference (m)a = area (m2)d = diameter (m)piA = 3.14159265APi is is a mathematical constant whose value is the ratio of any circle's circumference to its diameter. Shown here to 8 decimal places.See related links.
diameter
The Diameter
A chord in which the diameter is the largest
Perform and write down each of these steps: -- Multiply the radius of the circular end of the cylinder by 2 to get its diameter. -- Multiply the diameter of the cylinder's round end by (pi) to get its circumference. -- Multiply the circumference of the cylinder's round end by its length. -- Point out that the result is 282.6 .
Infinitely many. Each point on the circumference of a semicircle can be one end of a diameter and there are infinitely many points in a line segment of any length.
End points: (10, -4) and (2, 2) Midpoint: (6, -1) which is the centre of the circle Distance from (6, -1) to any of its end points = 5 which is the radius Therefore the Cartesian equation is: (x-6)^2 +(y+1)^2 = 25
In Euclidean geometry, a line has no end points - it is infinite in length.
The only diameter would be a line segment connecting the end points of the half-circle arc.