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y equals 4x+1 is a parallel line to y equals 4x.
f(x) = 2x2 + 4x - 7
2*2+4x-9=0 4x=9-4 4x=5 x=5/4
Assuming the missing symbol there is an equals sign, then we have: y - 2x2 - 4x = 4 We can find it's vertex very easily by solving for y, and finding where it's derivative equals zero: y = 2x2 + 4x + 4 y' = 4x + 4 0 = 4x + 4 x = -1 So the vertex occurs Where x = -1. Now we can plug that back into the original equation to find y: y = 2x2 + 4x + 4 y = 2 - 4 + 4 y = 2 So the vertex is at the point (-1, 2)
4x
2x2= 4
7
6
2(x - 2)(x + 4) = 0 x = 2, -4
The equation of such a line is [ Y = -4x plus any number].
what is the slope of the line that has the equation 4x+2y=12?
How about y = (x - 2)2 = x2 - 4x + 4 ? That is the equation of a parabola whose axis of symmetry is the vertical line, x = 2. Its vertex is located at the point (2, 0).