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How do you divide complex numbers?
When dividing complex numbers you must:Write the problem in fractional formRationalize the denominator by multiplying the numerator and denominator by the conjugate of the denominator.You must remember that a complex number times its conjugate will give a real number.a complex number 2+2i. the conjugate to this is 2-i1. Multiply both together gives a real number.(2+2i)(2-2i) = 4 -4i + 4i + (-4i2) (and as i2 = -1) = 8To divide a complex number by a real number simply divide the real parts by the divisor.(8+4i)/2 = (4+2i)To divide a real number by a complex number.1. make a fraction of the expression 8/(2+2i)2. multiply by 1. express 1 as a fraction of the divisor's conjunction. 8/(2+2i)*(2-2i)/(2-2i)3. multiply numerator by numerator and denominator by denominator.(16-16i)/84. and simplify 2-2i
What is the cartesian form of this complex no 1 plus i cube?
(1+i)3 = 1 + 3i - 3 - i = -2 + 2i This is a complex number, and therefore cannot be plotted on a Cartesian plane.
How do you convert the complex number to standard form 1 plus 2i over root2 plus i?
Multiply the numerator and denominator by the complex conjugate of the denominator ... [ root(2) minus i ]. This process is called 'rationalizing the denominator'.
What is conjugation of 7-2i?
The conjugate of a complex number can be found by multiplying the imaginary part by -1, then adding the "real" part back. (-2i) * -1 = 2i, so the conjugation is 7+2i
What is the solution set of the equation x2 minus 2x plus 5 equals 0?
Using the quadratic formula, you get the complex answers of 1 + 2i and 1 - 2i
The conjugate of the complex number 3 plus 2i is?
It is 3 minus 2i
Which one is greater number 2 plus 3i or 3 plus 2i?
the magnitude of a complex number is the square root of the sum of the squares of the real and imaginary parts. so......... (4+9)^.5 = ~3.6 and also (9+4)^.5 = ~3.6 so they are both the same.
Find the reciprocal of the complex number 3 plus 2i Give your answer in the usual a plus bi form?
It is 3/13 - 2/13*i
How do you divide complex numbers?
When dividing complex numbers you must:Write the problem in fractional formRationalize the denominator by multiplying the numerator and denominator by the conjugate of the denominator.You must remember that a complex number times its conjugate will give a real number.a complex number 2+2i. the conjugate to this is 2-i1. Multiply both together gives a real number.(2+2i)(2-2i) = 4 -4i + 4i + (-4i2) (and as i2 = -1) = 8To divide a complex number by a real number simply divide the real parts by the divisor.(8+4i)/2 = (4+2i)To divide a real number by a complex number.1. make a fraction of the expression 8/(2+2i)2. multiply by 1. express 1 as a fraction of the divisor's conjunction. 8/(2+2i)*(2-2i)/(2-2i)3. multiply numerator by numerator and denominator by denominator.(16-16i)/84. and simplify 2-2i
What is the cartesian form of this complex no 1 plus i cube?
(1+i)3 = 1 + 3i - 3 - i = -2 + 2i This is a complex number, and therefore cannot be plotted on a Cartesian plane.
How do you convert the complex number to standard form 1 plus 2i over root2 plus i?
Multiply the numerator and denominator by the complex conjugate of the denominator ... [ root(2) minus i ]. This process is called 'rationalizing the denominator'.
What is a multiplicative inverse of an imaginary number?
The same as for a real number: 1 divided by the number.For example, the multiplicative inverse (or reciprocal) of 2i is 1 / 2i = -(1/2)i.
What is conjugation of 7-2i?
The conjugate of a complex number can be found by multiplying the imaginary part by -1, then adding the "real" part back. (-2i) * -1 = 2i, so the conjugation is 7+2i
What is the real part of the complex number -2i?
It is 0. The number is wholly imaginary.
Can x to the fourth power ever result in a negative number?
no even exponent of a real number can ever result in a negative number. If x is a complex number with the real and imaginary part having the same magnitude, then taking that to the fourth power will result in a real number, which is negative.Example: (2 + 2i)4, or (-2 + 2i)4, or (2 - 2i)4, or (-2 - 2i)4, Just take (2 - 2i)4, as one to see how it works. First take (2 - 2i)2, then we'll square that result.(2 - 2i)2 = 4 - 4i - 4i + 4i2 , but i2 is -1, so we have -8i, then square that is 64i2 which is -64.
When the sum of the complex numbers 3 plus 2I and 6 - 4I is graphed in which quadrant does it lie?
3+2i + 6-4i = 9-2i The real part of this number is positive, therefore it lies in Q1 or Q4. The imaginary part is negative, therefore it is in Q3 or Q4. Q4 is the common possibility, therefore 9-2i is in Q4.
What is the solution set of the equation x2 minus 2x plus 5 equals 0?
Using the quadratic formula, you get the complex answers of 1 + 2i and 1 - 2i
