the magnitude of a complex number is the square root of the sum of the squares
of the real and imaginary parts. so.........
(4+9)^.5 = ~3.6 and also
(9+4)^.5 = ~3.6 so they are both the same.
It is 3 minus 2i
The multiplicative inverse of a number a is a number b such that axb=1 If we look at (3-4i)/(5+2i), we see that we can multiply that by its reciprocal and the product is one. So (5+2i)/(3-4i) is the multiplicative inverse of (3-4i)/(5+2i)
8.2462 (rounded)
The four roots are:1 + 2i, 1 - 2i, 3i and -3i.
10 + 6i and 7 + 2i = 10 + 6i + 7 + 2i = 17 + 8i
1.75 + 1.75i7i/2 + 2i = 3.5i + 2i = 5.5i
Yes. x2 + 4 = ( x + 2i ) times ( x - 2i ) where 'i' = the unit imaginary number = the square root of -1.
It is 3/13 - 2/13*i
(-2 + 3i) + (-1 - 2i) = -2 + 3i - 1 - 2i = -2 - 1 + 3i - 2i = -3 + i
3+2i + 6-4i = 9-2i The real part of this number is positive, therefore it lies in Q1 or Q4. The imaginary part is negative, therefore it is in Q3 or Q4. Q4 is the common possibility, therefore 9-2i is in Q4.
no even exponent of a real number can ever result in a negative number. If x is a complex number with the real and imaginary part having the same magnitude, then taking that to the fourth power will result in a real number, which is negative.Example: (2 + 2i)4, or (-2 + 2i)4, or (2 - 2i)4, or (-2 - 2i)4, Just take (2 - 2i)4, as one to see how it works. First take (2 - 2i)2, then we'll square that result.(2 - 2i)2 = 4 - 4i - 4i + 4i2 , but i2 is -1, so we have -8i, then square that is 64i2 which is -64.
-5-7=-126i-8i=-2i-12-2i is your final answer