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There are 10 digits, but for a three digit number the first number cannot be a 0.

Thus: there is a choice of 9 digits for the first (and last digit which must be the same), with

10 choices of digit for the second (middle) digit,

making 9 × 10 = 90 such palindromic numbers.

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Q: What is the maximum number of different three digit palindromes you can make using any digit?
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How many different palindromes are there with 6 digits?

For there to be palindromes, each digit must be replicated. Therefore there are at most three distinct digits.If there are 3 pairs of different digits, then there are 6 palindromes. If there can be more duplicate digits, then there are 27 palindromes.


How many 4-digit palindromes are there?

There are 90 four-digit palindromes


How many four digit palindromes are there?

There is 90 four digit palindromes.


How many four digit palindromes are perfect squares?

There are no four-digit perfect squares that are palindromes.


How many digits palindromes are there?

There are 90 four-digit palindromes


How many palindromes have 6 digits?

There are 900 6-digit palindromes.


How many 3-digit odd palindromes are divisible by 5?

There are 10 3-digit odd palindromes that are divisible by five.


What are examples of 3 digit numbers that transform into palindromes?

Any, and every, number can be transformed into a palindrome.


Are there more 11 digit or 12 digit palindromic numbers?

There are the same number: any twelve digit palindrome is just an eleven digit palindrome with its central digit repeated. In general, if we are considering numbers of n digits: For even values of n, the number of palindromes is 9 x 10n/2 - 1 For odd values of n, the number of palindromes is 9 x 10(n-1)/2


How many 5 digit palindromes are there?

900 This explains it. A positive integer is a palindrome if it reads the same forward and backwards such as 1287821 and 4554. Determine the number of 5-digit positive integers which are NOT palindromes. We start by counting the total number of 5 digit positive integers. The first digit is between 1 and 9, so we have 9 choices. Each of the other 4 digits can be anything at all (10 choices for each). This gives us 9(10)4 = 90000 five-digit positive integers. Now we need to count the number of 5 digit palindromes. Again, we have 9 choices for the first digit and 10 choices for each of the next two. The tens and units digits however are fixed by our choices so far. Therefore, there are only 900 five-digit palindromes. Therefore, the total number of five-digit positive integers which are not palindromes is 90000-900 = 89100.


Are there more 10-digit or 11-digit palindromic numbers?

-1


Can 100 different digits make 100 multiplied by 100 equal 10000 different three digits palindromes?

Yes. But that is true only if the 100 digits do not include 0. Or, if 0 is included, then you consider "0n0" to be a three digit number. Most people would consider is to be a 2-digit number.