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There are 900 6-digit palindromes.

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Q: How many palindromes have 6 digits?
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How many different palindromes are there with 6 digits?

For there to be palindromes, each digit must be replicated. Therefore there are at most three distinct digits.If there are 3 pairs of different digits, then there are 6 palindromes. If there can be more duplicate digits, then there are 27 palindromes.


How many digits palindromes are there?

There are 90 four-digit palindromes


How many 4 digit palindromes are multiples of 9?

Nine. The sum of the digits must be a multiple of 9; because of the repeated digits, this is only possible if the first two digits add up to 9.


How many positive four-digit integer palindromes have 12 as the sum of the digits of the munber?

81


How many palindromes are there from 100 to 159?

6.


How many digits are in 29,400?

6 digits


How many ten digit palindromes are there?

90000. With 10 digit palindromes, the last 5 digits are the same as the first 5 digits in reverse, eg 12345 54321. So it comes down to how many 5 digit numbers are there? They are the numbers "10000" to "99999", a total of 99999 - 10000 + 1 = 90000.


How many three-digit palindromes can you make using only the digits 1 and 2?

111, 121, 222, 212


What are some 6 letter palindromes?

Some 6 letter palindromes you may like:RedderHannah


How many five digit even palindromes are there?

There are 400. Assuming the number must be at least 10,000, then: In a 5 digit palindrome, the first and last digits must be the same, and the second and fourth digits must be the same; and: For the first and last digit there is a choice of 4 digits {2, 4, 6, 8}; For each of these there is a choice of 10 digits {0, 1, ..., 9} for the second and fourth digits; For each of the above choices these is a choice of 10 digits {0, 1, ..., 9} for the third digit; Making 4 x 10 x 10 = 400 possible even 5 digit palindromes.


How many different three digit palindromes can you make using only the digits 1and 2?

There are two possible digits for the first and last digit, and two possible digits for the centre digit, making 2 × 2 = 4 possible 3 digit palindromes from the set {1, 2}, namely the set {111, 121, 212, 222}.


How many different three-digit palindromes can you make using only the digits 1 and 2?

111, 121, 212, 222