Given ANY number at all, it is possible to find a cubic polynomial such that that particular number is the nth number in a sequence starting with the above three.
The simplest rule, however, is Un = 5n + 9
Assuming the pattern would continue: 25, 24, 23, 22, 21, 20, 19, 18, 17, 16, 15, 14, 13...
If you mean: 6 12 18 24 then the nth term is 6n
The nth term of that series is (24 - 6n).
If you mean: 34 39 24 ... then the nth term is 39-5n and so the 100th term = -461
The lowest term of 14 over 24 is 7/12.
Assuming the pattern would continue: 25, 24, 23, 22, 21, 20, 19, 18, 17, 16, 15, 14, 13...
29
The nth term is (36 - 4n)
If you mean: 6 12 18 24 then the nth term is 6n
The nth term of that series is (24 - 6n).
24-5n
each time the number increases by 8 and the original number was 3.This means that nth term = 3+(n-1)8ie. the fourth term 27 would be 3 + (4-1)x8 = 3+24 = 27
It goes up by (24-16) = 8 each time. The first time is 16. So the nth term is 8n + 8.
0,3,8,15,24,27,32,41
44
You can see that you add 10 to the previous term to get the next term. Term number 1 2 3 4 Term 4 14 24 34 You can also say: Term number 1 2 3 4 Term 0*10+4 1*10+4 2*10+4 3*10+4 So the nth term would be 10(n-1)+4 Or if you expand it, it's 10n-6
Give the simple formula for the nth term of the following arithmetic sequence. Your answer will be of the form an + b.12, 16, 20, 24, 28, ...