t(n) = 29 - 7n where n = 1, 2, 3, ...
(n^2+n)/2
The nth term of that series is (24 - 6n).
If you mean: 6 12 18 24 then the nth term is 6n
The nth term of an AP with initial term a (= u{1}) and common difference d is given by: u{n} = a + (n - 1)d In this case: a = 6 d = (12 - 6) = 6 → u{n} = 6 + (n - 1)6 But this can be simplified: u{n} = 6 + (n - 1)6 = 6 + 6n - 6 = 6n
It is: nth term = 29-7n
The nth term is -7n+29 and so the next term will be -6
3n
The nth term is 18 -3n and so the next term will be 3
The given sequence is an arithmetic sequence with a common difference of 6. To find the nth term of this sequence, we can use the following formula: nth term = first term + (n - 1) x common difference where n is the position of the term we want to find. In this sequence, the first term is 1 and the common difference is 6. Substituting these values into the formula, we get: nth term = 1 + (n - 1) x 6 nth term = 1 + 6n - 6 nth term = 6n - 5 Therefore, the nth term of the sequence 1, 7, 13, 19 is given by the formula 6n - 5.
nth term= 6 + (n-1) (2)
6 = 2 * 3 15 = 3 * 5 28 = 4 * 7 45 = 5 * 9 66 = 6 * 11 Assuming the pattern continues, the nth term is (n + 1) * (2n +1) = 2n^2 + 3n + 1.
7n - 6
t(n) = 29 - 7n where n = 1, 2, 3, ...
35 * * * * * That is the next term. The question, however, is about the nth term. And that is 6*n - 1
The nth term of the sequence is (n + 1)2 + 2.
The nth term in this arithmetic sequence is an=26+(n-1)(-8).