The nth term of the sequence is (n + 1)2 + 2.
43
The nth term is: n^2 +2 and so the next number will be 38
each time the number increases by 8 and the original number was 3.This means that nth term = 3+(n-1)8ie. the fourth term 27 would be 3 + (4-1)x8 = 3+24 = 27
ans=102 HOW? 6,11,13,27,38,.... 6(+5),11(+7),13(+9),27(+11),38(+13),51(+15),66(+17),83(+19),102adding 5 to 6 gives 11 adding 7(two greater than previous one) gives 13...and so on... to find the nth term N squared +2
n3
5n+2
The nth term is: n^2 +2 and so the next number will be 38
each time the number increases by 8 and the original number was 3.This means that nth term = 3+(n-1)8ie. the fourth term 27 would be 3 + (4-1)x8 = 3+24 = 27
ans=102 HOW? 6,11,13,27,38,.... 6(+5),11(+7),13(+9),27(+11),38(+13),51(+15),66(+17),83(+19),102adding 5 to 6 gives 11 adding 7(two greater than previous one) gives 13...and so on... to find the nth term N squared +2
(n(n-1) divided by 2 + 1) multiplied by 3) +6
n3
5n+2
Willies
2n +29
There are many possible answers, but the simplest is t(n) = 27 - 8*n where n = 1, 2, 3, ...
Subtract 2 from the sequence and the answer becomes obvious: 1, 4, 9, 16, 25,...,N2 Now, add the 2 back in: 3, 6, 11, 18, 27,...,(N2+2)
3^n These are powers of 3
the anser is that you are stupid