It is: 26-6n
They are: nth term = 6n-4 and the 14th term is 80
3n-2
20-9x=n
By varying the parameters of a quartic polynomial, the nth term can be made whatever you like. But, taking the simplest solution, Un = 2 - 4n for
To find the nth term of the sequence 5, 15, 29, 47, 69, we first determine the differences between consecutive terms: 10, 14, 18, and 22. The second differences are constant at 4, indicating that the nth term is a quadratic function. By fitting the quadratic formula ( an^2 + bn + c ) to the sequence, we find that the nth term is ( 2n^2 + 3n ). Thus, the nth term of the sequence is ( 2n^2 + 3n ).
They are: nth term = 6n-4 and the 14th term is 80
It is: nth term = -4n+14
The nth term is: 3n+2 and so the next number will be 20
f(n) = 14 - 6n -6n+20
The nth term is 2 + 3n.
The nth term is 3n+2 and so the next number will be 17
42
t(n) = 10 - 6n where n = 1, 2, 3, ...
It is: 3n+2
3n-2
20-9x=n
By varying the parameters of a quartic polynomial, the nth term can be made whatever you like. But, taking the simplest solution, Un = 2 - 4n for