Any number that you choose can be the next number. It is easy to find a rule based on a polynomial of order 5 such that the first five numbers are as listed in the question followed by the chosen next number. There are also non-polynomial solutions. Short of reading the mind of the person who posed the question, there is no way of determining which of the infinitely many solutions is the "correct" one.
If you want it to be 1, use the following rule:
t(n) = (n^5 - 15*n^4 + 85*n^3 - 225*n^2 + 218*n - 104)/8
If you want the next number to be 100, use
t(n) = (19*n^5- 285*n^4 + 1615*n^3 - 4275*n^2 + 5066*n - 1720)/20
In this particular case, the answer is probably based on the linear rule,
t(n) = -7n + 28, and if that is the case, the next number is -14.
12 and a halfpigs earmonkey buisnessthese really shouldnt be publicoinkrabbit rabiitwoof woofneigh
The nth term of that series is (24 - 6n).
n - 1
7 - 4n where n denotes the nth term and n starting with 0
n-9+3
12 and a halfpigs earmonkey buisnessthese really shouldnt be publicoinkrabbit rabiitwoof woofneigh
n2-4
The nth term of that series is (24 - 6n).
0
0,3,8,15,24,27,32,41
n - 1
7 - 4n where n denotes the nth term and n starting with 0
If the nth term is 8 -2n then the 1st four terms are 6, 4, 2, 0 and -32 is the 20th term number
24 - 6n
n-9+3
-4, -3, 0, 5, 12, 21, 32
You can see that you add 10 to the previous term to get the next term. Term number 1 2 3 4 Term 4 14 24 34 You can also say: Term number 1 2 3 4 Term 0*10+4 1*10+4 2*10+4 3*10+4 So the nth term would be 10(n-1)+4 Or if you expand it, it's 10n-6