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One of the infinitely many possible rules for the nth term of the sequence is t(n) = 4n - 1
Strangely enough, it is 9n + 1 for n = 1, 2, 3, ...
7 - 4n where n denotes the nth term and n starting with 0
The nth term of the sequence is 3n-8 and so the 30th term is 3*30 -8 = 82
This is the Fibonacci sequence, where the number is the sum of the two preceding numbers. The nth term is the (n-1)th term added to (n-2)th term
The nth term of the sequence is 2n + 1.
12 - 5(n-1)
One of the infinitely many possible rules for the nth term of the sequence is t(n) = 4n - 1
I suspect that the first term should be "negative 3", ie the sequence is -3, 1, 5, 9, 13, 17, ... The nth term is 4n - 7
The nth term is 4n-1 and so the next term will be 19
If 3 is the first term, then the nth term is [ 3 x 2(n-1) ] .
The nth term in this sequence is 4n + 3.
If 3 is the first term, then the nth term is [ 3 x 2(n-1) ] .
The nth term of a sequence is the general formula for a sequence. The nth term of this particular sequence would be n+3. This is because each step in the sequence is plus 3 higher than the previous step.
9
The nth term for that arithmetic progression is 4n-1. Therefore the next term (the fifth) in the sequence would be (4x5)-1 = 19.
The nth term is 5n-3 and so the next term will be 22